Find all School-related info fast with the new School-Specific MBA Forum

It is currently 25 Oct 2014, 20:33

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

Probability - GMAT Practice Questions

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:
Senior Manager
Senior Manager
User avatar
Status: Time to step up the tempo
Joined: 24 Jun 2010
Posts: 410
Location: Milky way
Schools: ISB, Tepper - CMU, Chicago Booth, LSB
Followers: 7

Kudos [?]: 119 [0], given: 50

Probability - GMAT Practice Questions [#permalink] New post 27 Aug 2010, 18:39
00:00
A
B
C
D
E

Difficulty:

  45% (medium)

Question Stats:

50% (01:33) correct 50% (00:45) wrong based on 14 sessions
Question: James and Colleen are playing basketball. The probability of James missing a shot is x, and the probability of Colleen not making a shot is y. If they each take 2 shots. What is the probability that they both make at least 1 shot apiece?

A) 1 - (x^2*y^2)
B) (1-x^2) (1-y^2)
C) (1-(1-x)^2) (1- (1-y)^2)
D) (1-(1-x)^2) ((1-y)^2)
E) (1-(1-y^2)) (1-x^2)

I could not solve this problem and I wanted to arrive at the answer using the algebraic route and by not picking numbers.
[Reveal] Spoiler: OA

_________________

:good Support GMAT Club by putting a GMAT Club badge on your blog :thanks

1 KUDOS received
GMAT Instructor
avatar
Joined: 24 Jun 2008
Posts: 978
Location: Toronto
Followers: 261

Kudos [?]: 710 [1] , given: 3

Re: Probability - GMAT Practice Questions [#permalink] New post 27 Aug 2010, 19:35
1
This post received
KUDOS
ezhilkumarank wrote:
Question: James and Colleen are playing basketball. The probability of James missing a shot is x, and the probability of Colleen not making a shot is y. If they each take 2 shots. What is the probability that they both make at least 1 shot apiece?

A) 1 - (x^2*y^2)
B) (1-x^2) (1-y^2)
C) (1-(1-x)^2) (1- (1-y)^2)
D) (1-(1-x)^2) ((1-y)^2)
E) (1-(1-y^2)) (1-x^2)

I could not solve this problem and I wanted to arrive at the answer using the algebraic route and by not picking numbers.


The probability James misses both shots is x*x = x^2. So the probability James makes at least one shot is 1 - x^2. Similarly, the probability Colleen makes at least one shot is 1 - y^2. To find the probability they both make at least one shot, we multiply the probability that each makes at least one shot: (1 - x^2)(1 - y^2).
_________________

Nov 2011: After years of development, I am now making my advanced Quant books and high-level problem sets available for sale. Contact me at ianstewartgmat at gmail.com for details.

Private GMAT Tutor based in Toronto

Senior Manager
Senior Manager
User avatar
Status: Time to step up the tempo
Joined: 24 Jun 2010
Posts: 410
Location: Milky way
Schools: ISB, Tepper - CMU, Chicago Booth, LSB
Followers: 7

Kudos [?]: 119 [0], given: 50

Re: Probability - GMAT Practice Questions [#permalink] New post 27 Aug 2010, 20:16
IanStewart wrote:
ezhilkumarank wrote:
Question: James and Colleen are playing basketball. The probability of James missing a shot is x, and the probability of Colleen not making a shot is y. If they each take 2 shots. What is the probability that they both make at least 1 shot apiece?

A) 1 - (x^2*y^2)
B) (1-x^2) (1-y^2)
C) (1-(1-x)^2) (1- (1-y)^2)
D) (1-(1-x)^2) ((1-y)^2)
E) (1-(1-y^2)) (1-x^2)

I could not solve this problem and I wanted to arrive at the answer using the algebraic route and by not picking numbers.


The probability James misses both shots is x*x = x^2. So the probability James makes at least one shot is 1 - x^2. Similarly, the probability Colleen makes at least one shot is 1 - y^2. To find the probability they both make at least one shot, we multiply the probability that each makes at least one shot: (1 - x^2)(1 - y^2).



Thanks IanStewart. +1 from me.
_________________

:good Support GMAT Club by putting a GMAT Club badge on your blog :thanks

Re: Probability - GMAT Practice Questions   [#permalink] 27 Aug 2010, 20:16
    Similar topics Author Replies Last post
Similar
Topics:
25 Experts publish their posts in the topic Practice questions of Combinations and probability Narenn 8 04 Apr 2013, 03:40
1 Practice Questions -- Embarrasingly simple, probably mijou 4 03 Mar 2011, 19:56
GMATprep practice question:probability pmal04 2 25 Apr 2009, 15:28
Manhattan Gmat Probability question apollo168 6 31 Jul 2006, 23:34
manhattan GMAT probability question wlee76 7 03 Jan 2006, 02:30
Display posts from previous: Sort by

Probability - GMAT Practice Questions

  Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.