So, this is an easy question I'm totally brain-farting on...

If two fair, six-sided dice are rolled, what is the probability that the sum of the numbers will be 5?

A)

\frac{1}{6}B)

\frac{1}{4}C)

\frac{1}{36}D)

\frac{1}{18}E)

\frac{1}{9}I'm guessing you could find the probability of getting a 1 AND 4 and add it to the probability of rolling 2 AND 3...which yields

\frac{1}{18}.

...or do I need to add the probability of getting a 4 AND 1 and 3 AND 2, which yields

\frac{1}{9}?

I tried doing the desired outcome over all possible outcomes:

[You can get sums to equal 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, or 12.]

2: 1+1

3: 1 + 2, 2+1

4: 1+3, 3+1, 2+2

5: 1+4, 4+1, 2+3, 3+26: 1+5, 5+1, 2+4, 4+2, 3+3

7: 1+6, 6+1, 2+5, 5+2, 3+4, 4+3

8: 2+6, 6+2, 3+5, 5+3, 4+4

9: 3+6, 6+3, 4+5, 5+4

...

12: 6+6

Total number of outcomes: 36

Number of desired outcomes: 4

Therefore, the probability is

\frac{1}{9}, correct?

_________________

My GMAT quest...

...over!