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Probability theory

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Probability theory [#permalink] New post 18 Jan 2013, 06:37
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In probability questions, specifically OR problems (addition problems), the formula is:

P(A or B) = P(A) + P(B) - P(A AND B)

Why do we have to substract P(A AND B)?, I think we do that because P(A) and P(B) already include P(A AND B), right?

Please, confirm.
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Re: Probability theory [#permalink] New post 18 Jan 2013, 07:39
danzig wrote:
In probability questions, specifically OR problems (addition problems), the formula is:

P(A or B) = P(A) + P(B) - P(A AND B)

Why do we have to substract P(A AND B)?, I think we do that because P(A) and P(B) already include P(A AND B), right?

Please, confirm.


correct.
p(a) and p(b) both include p(a & b). so essentially when you want to write p(a or b), you mean p(only a)+p(only b)+p(a&b). ---1

where as, p(a)+p(b)= [p(only a)+ p(a&b)] + [p(only b)+p(a&b)]

hence you want to subtract p(a&b) from p(a)+p(b) to obtain equation #1.

Hope its clear. You should also try making a Venn diagram; that shall make this a bit more easier.
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Re: Probability theory [#permalink] New post 21 Jan 2013, 05:04
Expert's post
danzig wrote:
In probability questions, specifically OR problems (addition problems), the formula is:

P(A or B) = P(A) + P(B) - P(A AND B)

Why do we have to substract P(A AND B)?, I think we do that because P(A) and P(B) already include P(A AND B), right?

Please, confirm.


Yes, it is the same as the sets concept:

n(A or B) = n(A) + n(B) - n(A and B)

n(A) and n(B) both include n(A and B). You cannot double count it so you must subtract it once. Check out this sets post to see how it is represented in the venn diagram:
http://www.veritasprep.com/blog/2012/09 ... s-of-sets/

If you need to find the probability of 'A or B but not both', you will need to subtract P(A and B) twice.

P(A or B but not both) = P(A) + P(B) - 2*P(A and B)
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Re: Probability theory   [#permalink] 21 Jan 2013, 05:04
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