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x,y and z each try independantly to solv a problem.If their individual probabilities for success are 1/4,1/2 and 5/8 resp.,what is the probability that x and y but not z will solve the problem?
Guys this is my approach where am I going wrong?
Z does not solve the problem=only X solves it+ only Y solves it + both x and Y solve it.
=7/8...which is the wrong ans...