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Problem solving question (m25-35) [#permalink]
19 Jan 2010, 19:07
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Question Stats:
72% (01:36) correct
27% (00:41) wrong based on 76 sessions
If M and N are positive integers, then is M an even integer? 1. \frac{M}{N} is an odd integer. 2. M + N is an even integer. Source: GMAT Club Tests - hardest GMAT questions I picked A as the solution, as M and N have to be odd for M/N to be odd. Please advice if someone has a different solution.
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Re: Problem solving question [#permalink]
20 Jan 2010, 04:29
suhasrao wrote: If M and N are positive integers, then is M an even integer? 1. M/N is an odd integer. 2. M+N is an even integer.
stmnt1 - M/N is odd here if N = 1 then M will be odd but if N is 2 then M will be even[ 6,10 etc]. hence insuff stmnt2 - M+N is even here also M and N can be both odd or even. Hence insuff taking together we have if N = 1 let M = 5 then M/N is odd and M+N is even if N =2 and M = 6 then M/N is odd and M+N is even so M can be both even or odd. will go with E
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Re: Problem solving question [#permalink]
20 Jan 2010, 04:35
1) M and N Could be both odd or both even. Consider following examples: 10/2 = 5; 15/5=3. Therefore we cannot determine whether M is even
2) Same case here: M,N are both odd OR both even. consider following: 10+2=12; 15+5=20. That is a dead-end too
Combining the statements is fruitless. We can't narrow down possibilities.
It's (E)
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Re: Problem solving question [#permalink]
20 Jan 2010, 04:53
Hi, When you post a question from the GMAT Club Tests the next time, please indicate the Test and question number. For example, this one should have "m25-35" or something similar in the thread title. Thank you for cooperation. suhasrao wrote: If M and N are positive integers, then is M an even integer? 1. M/N is an odd integer. 2. M+N is an even integer.
* Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient * Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient * BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient * EACH statement ALONE is sufficient * Statements (1) and (2) TOGETHER are NOT sufficient
I picked A as the solution, as M and N have to be odd for M/N to be odd.
Please advice if someone has a different solution.
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Re: Problem solving question (m25-35) [#permalink]
21 Jan 2010, 22:11
I went with E as well by plugging in a few combos of m and n that work for both 1 and 2. (m,n) (6,3);(5,1);(6,2);(9,3);(33,11).
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Re: Problem solving question (m25-35) [#permalink]
15 Sep 2010, 05:56
E statement 1 and 2 hold true for M being Even and Odd, for Both. I used egs - 21/7, 10/5 and 10/2, couldn conclude. Statement 1 - Odd/Odd = Odd ; Even/Even = Odd/Even; 21/7 and 10/2 Statement 2 - Odd + Odd = Even; Even + Even = Even; 21 + 7 = 28; 10 + 2 = 12. With Both statements together - Assuming M/N - Odd (21/7 & 10/2) M can be even or Odd (10 or 21) and Statement 2 is still TRUE. Hence "E"
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Re: Problem solving question (m25-35) [#permalink]
15 Sep 2010, 07:59
E
statement 1 and 2 hold true for M being Even and Odd, for Both.
I used - 21/7, 3/3 and 10/2, couldn conclude.
Statement 1 - Odd/Odd = Odd ; Even/Even = Odd/Even; 21/7 and 10/2 Statement 2 - Odd + Odd = Even; Even + Even = Even; 21 + 7 = 28; 10 + 2 = 12.
With Both statements together - Assuming M/N - Odd (21/7 & 10/2)
M can be even or Odd (10 or 21) and Statement 2 is still TRUE.
Hence "E"
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Re: Problem solving question (m25-35) [#permalink]
15 Sep 2010, 08:41
E by plugging even & odd numbers.
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Re: Problem solving question (m25-35) [#permalink]
15 Sep 2010, 09:07
E by using 6,2 and 9,3 values Posted from my mobile device
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Re: Problem solving question (m25-35) [#permalink]
15 Sep 2010, 15:13
E. (1). If M/N = odd, then we have Odd/Odd = Odd (49/7 = 7) or Even/Even = Odd (6/2 = 3). So M and N are Odd/Odd or Even/Even. (2). If M + N = Even, then we have the same information. Odd + Odd = Even (3+5 = 8) and Even + Even = Even (4+6 = 10). Combine then both together and we still don't know whether M, N are odd or M, N are even. (From above we know if both were true then M would be what N is, so knowing either would answer the question. We know neither.)
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Re: Problem solving question (m25-35) [#permalink]
20 Sep 2011, 18:57
easy one..answer is E
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Re: Problem solving question (m25-35) [#permalink]
22 Mar 2012, 20:46
just place examples into each situation. 1. M/N use 18/2 = 9 odd so M is even or 15/5 = 3 odd so M is odd. Insufficient 2. only odd + odd or even + even can equal even. insufficient. combined both say the same thing that m and n are both odd or both even but no specific on which one.
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Re: Problem solving question (m25-35) [#permalink]
27 Mar 2012, 02:46
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Re: Problem solving question (m25-35) [#permalink]
19 Sep 2012, 06:49
I ruled out A and B.
When it came to C, we know M/N = odd
From 1, M = N * Odd
From 2, M = Even - N
Combining both, N * Odd = Even - N N (Odd + 1) = Even N * (Even) = Even
Since we know N is an integer, E/E = Even or Odd
Answer is E.
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Re: Problem solving question (m25-35) [#permalink]
19 Sep 2012, 12:16
great explanation by Bunuel , Without confusion it can be solved by his way.
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Re: Problem solving question (m25-35) [#permalink]
19 Sep 2012, 12:17
great explanation by Bunuel , Without confusion it can be solved by his way.Kudos +1 to you.
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Re: Problem solving question (m25-35) [#permalink]
20 Sep 2012, 06:38
We need to remember a few scenarios. Every other scenario gives you EVEN. A) ODD X ODD = ODD (This automatically implies that ODD/ODD = ODD, assuming that the denominator is a factor of numerator) B) ODD +- EVEN = ODD c) EVEN/EVEN = TROUBLE-MAKER (Watch out for this guy, the result is unpredictable ) d) ZERO is considered EVEN. BUT ZERO is neither positive nor negative, its just ZERO
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Re: Problem solving question (m25-35)
[#permalink]
20 Sep 2012, 06:38
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