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3. Fresh Grapes contain 90% water and 10% grape pulp whereas Dry Grapes
contain 20% water and 80% grape pulp. How many kgs of Dry Grapes can
be obtained from 20 kgs of Fresh Grapes?
_________________

Amount of grape pulp will remain same. 80Z/100 =10/100*20 z=2.5

Answer is 2.5 kgs

As simple as that....................

Here comes our next question

4. A group of men can complete a work in certain number of days. After they
worked for 12 days 1/4 of them left. To complete the remaining work the
remaining men have taken as many days as the initial number of men
would have taken to complete the entire work. In how many days is the
work completed?
_________________

very tough quest indeed
I find that the radius of the bigger circle is 5
I think this is not a kind of GMAT quest (easy math prob but take too much time and paper also)

We can use the "reduiced" Delta = 3^2 - 5*1 = 4 = 2^2

Thus, we have 2 possibilies :
o r= (3+2)/1 = 5
o r= (3-2)/1 = 1

For the latter radius, the vertex lying on the circle is represented by a point on the "other side" of the circle. In the case of this picture, the radius is 5.

I m not clear how you can take the cordinates of vertex as (2 , 1) since 2 and 1 are the length of the rectangle and you are taking the center of the circle as the origin. Even by Visual observation I am not able to understand the login.. Can you please explain ..?

I m not clear how you can take the cordinates of vertex as (2 , 1) since 2 and 1 are the length of the rectangle and you are taking the center of the circle as the origin. Even by Visual observation I am not able to understand the login.. Can you please explain ..?

Regards, Amit

I take the origine O(0,0) at the point C : the vertex of the scare at the bottom left

Since this origine definied,
o the vertex of a silimar little rectangle from C and on the circle has the coordinates (2,1) (lenght, width).
o the center of the cicle Z is at (r,r)

A group of men can complete a work in certain number of days. After they worked for 12 days 1/4 of them left. To complete the remaining work the remaining men have taken as many days as the initial number of men would have taken to complete the entire work. In how many days is the work completed?

I tried like this:

r (12) = w
.75r (t - 12) = w ---> .75rt - 9r = 12r ---> rt = 28r ---> t = 28

t = 28 + 12 = 40

I see this is the wrong answer. Should I not have set the two equations equal to one another? Can someone suggest how to correct this