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# Problem solving work problem

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Joined: 02 Sep 2010
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Problem solving work problem [#permalink]  30 Nov 2010, 06:03
00:00

Difficulty:

25% (medium)

Question Stats:

100% (02:24) correct 0% (00:00) wrong based on 9 sessions
Pumping alone at their respective constant rates, one inlet pipe fills an empty tank to 1/2 of capacity in 3 hours and a second inlet pipe fills the same empty tank to 2/3 of capacity in 6 hours. How many hours will it take both pipes, pumping simultaneously at their respective constant rates, to fill the empty tank to capacity?

A. 3.25
B. 3.6
C. 4.2
D. 4.4
E. 5.5
[Reveal] Spoiler: OA
Intern
Joined: 30 Nov 2010
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Re: Problem solving work problem [#permalink]  30 Nov 2010, 06:19
1/2 of capacity in 3 hours

full capacity in 6 hours

---> pump A.

2/3 capacity in 6 hours

(2/3 +1/3) in 6+3 = 9 hours

---> pump B

in 1 hour filled 1/6 +1/9 = 5/18 parts
full in 18/5 hours 3.6 hrs.

HTH
Manager
Status: I rest, I rust.
Joined: 04 Oct 2010
Posts: 121
Schools: ISB - Co 2013
WE 1: IT Professional since 2006
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Re: Problem solving work problem [#permalink]  30 Nov 2010, 06:30
Inlet 1 fills x/6 in 1 hour
inlet 2 fills (2x/3)/6 = x/9 in 1 hour

so together in 1 hour they will fill x/6 + x/9 = 5x/18
which means to fill 5x/18 it takes 1 hour => to fill x it will take 18/5=3.6 hrs
_________________

Respect,
Vaibhav

PS: Correct me if I am wrong.

Re: Problem solving work problem   [#permalink] 30 Nov 2010, 06:30
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