Question : Of the three digit integers greater than 700, how many have two digits that are equal to each other and the remaining digit different from the other two?
How do I go about setting this up
I guess a table
701-799 800-899 900-999
You are right that is the range.
Total number in 800-899 range = 9 (tenth digit and unit digit are same and not equal to 8)
+ 9 (hundredth digit and unit digit are same=8 and tenth digit not equal to 8) +9 ( hundredth didgit and tenth digit =8 and unit digit not equal to 8)
Total number = 27+27+27 -1 = 80
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