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# PS - 1000Q

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Director
Joined: 05 Feb 2006
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05 Nov 2006, 10:08
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Xavier, Yvonne, and Zelda each try independently to solve a problem. If their individual probabilities for success are 1/4 , 1/2 , and 5/8 , respectively, what is the probability that Xavier and Yvonne, but not Zelda, will solve the problem?

(A) 11/8
(B) 7/8
(C) 9/64
(D) 5/64
(E) 3/64
Director
Joined: 05 Feb 2006
Posts: 898
Followers: 3

Kudos [?]: 107 [0], given: 0

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05 Nov 2006, 10:25
yogeshsheth wrote:
1/4*1/2*3/8 =3/64

This was utterly simple

1-5/8=3/8... than multiply everything... thanks.
VP
Joined: 25 Jun 2006
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06 Nov 2006, 00:14
yes. it is E.
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