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PS - 1000Q

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Director
Director
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Joined: 05 Feb 2006
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PS - 1000Q [#permalink] New post 05 Nov 2006, 10:08
00:00
A
B
C
D
E

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(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
Xavier, Yvonne, and Zelda each try independently to solve a problem. If their individual probabilities for success are 1/4 , 1/2 , and 5/8 , respectively, what is the probability that Xavier and Yvonne, but not Zelda, will solve the problem?

(A) 11/8
(B) 7/8
(C) 9/64
(D) 5/64
(E) 3/64
Director
Director
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 [#permalink] New post 05 Nov 2006, 10:25
yogeshsheth wrote:
1/4*1/2*3/8 =3/64


This was utterly simple :)

1-5/8=3/8... than multiply everything... thanks.
VP
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 [#permalink] New post 06 Nov 2006, 00:14
yes. it is E. :)
  [#permalink] 06 Nov 2006, 00:14
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