ps : GMAT Problem Solving (PS)

Oldest

Best Reply

Author

Message

TAGS:

Senior Manager

Joined: 30 Aug 2003

Posts: 348

Location: dallas , tx

Followers: 1

Kudos [?]: 2 [0], given: 0

ps [#permalink]

10 Dec 2003, 11:16

00:00

Question Stats:

0% (00:00) correct

0% (00:00) wrong

based on 0 sessions

The weight of a glass jar is 20% of the weight of the jar filled with coffee beans. After some of the beans have been removed, the weight of the jar and the remaining beans is 60% of the original total weight. What fractional part of the beans remain in the jar?
1/12
1/3
2/5
1/2
2/3
_________________

shubhangi

Manager

Joined: 26 Aug 2003

Posts: 238

Location: United States

Followers: 1

Kudos [?]: 1 [0], given: 0

[#permalink]

11 Dec 2003, 12:52

1/2?

j = weight of empty jar
b = weight of beans
A = weight of jar full of beans

A = j + b
A = j + 4j .... we're told weight of jar is 20% that of when it's full so b = 4j or 80% of the weight
A = 5j

After emptying some 60% left:

A = j + b
5j = j + b .... from above calculation
3j = j + b .... simply take 60% of 5
2j = b

This tells us half as many beans are left in the jar after emptying a little.

Director

Joined: 14 Oct 2003

Posts: 601

Location: On Vacation at My Crawford, Texas Ranch

Followers: 1

Kudos [?]: 2 [0], given: 0

[#permalink]

11 Dec 2003, 13:38

Pick a number
100 = total weight of jar when filled with beans
Therefore, 20 = empty, 80 = weight of beans.

after beans removed = 60; therefore 40 is the weight of beans removed thus only half of the beans + plus the tare weight of the jar remains.

1/2

Senior Manager

Joined: 30 Aug 2003

Posts: 348

Location: dallas , tx

Followers: 1

Kudos [?]: 2 [0], given: 0

[#permalink]

11 Dec 2003, 14:52

My method was same as titleist.. so 1/2 is correct...hope so.
coz answer to this question is also not given.
_________________

shubhangi

CEO

Joined: 15 Aug 2003

Posts: 3549

Followers: 55

Kudos [?]: 627 [0], given: 781

Re: ps [#permalink]

13 Dec 2003, 00:30

shubhangi wrote:

Total weight = weight of coffee jar = 100
Weight of glass jar = 20
Weight of the coffee beans = 80... (100-20)...............(a)
Original total weight = 100
New weight = 60% * 100 = 60
New weight of the beans = 40 ( 60-20).............(b)
Fraction =40/80 =1/2

thanks
praetorian

SVP

Joined: 30 Oct 2003

Posts: 1963

Location: NewJersey USA

Followers: 3

Kudos [?]: 25 [0], given: 0

[#permalink]

13 Jan 2004, 09:10

G = 0.2( G + C )
After some beans were removed C1 beans remained
so
G+C1 = 0.6(G+C)
C1 = 0.6(G+C) - G = 0.6(G+C) - 0.2(G+C) = 0.4(G+C)
so
C1/(G+C) = 0.4 = 2/5 ( I think this is what Geethu did )

But the question is asking C1/C
Since C = 4G
C1/C = 0.4 * 5 / 4 = 1/2

[#permalink] 13 Jan 2004, 09:10

	Similar topics	Author	Replies	Last post
Similar Topics:	PS	mistdew	3	01 Aug 2003, 08:47
	Ps	zxiaoli1	3	04 Sep 2003, 14:08
	Ps	shubhangi	1	15 Dec 2003, 13:12
	Ps	shubhangi	2	19 Dec 2003, 14:21
	ps	shubhangi	4	28 Dec 2003, 16:48

Main navigation

GMAT Resources

Partners

MBA Resources

GMAT ® is a registered trademark of the Graduate Management Admission Council ® (GMAC ®). GMAT Club's website has not been reviewed or endorsed by GMAC.

GMAT Courses

Admissions Consulting

ps

ps

Main navigation

GMAT Resources

Partners

MBA Resources