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# ps

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Manager
Joined: 26 Dec 2003
Posts: 227
Location: India
Followers: 1

Kudos [?]: 2 [0], given: 0

ps [#permalink]  21 Feb 2004, 15:26
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Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
If (a+b):(b+c):(c+a)=6:7:8 and a+b+c=14, then find a:b:c?
Manager
Joined: 26 Dec 2003
Posts: 227
Location: India
Followers: 1

Kudos [?]: 2 [0], given: 0

it is a+b : b+c : c+a. the question looked funny when i saw it now. Need to improve my typing skills.
Manager
Joined: 16 Jan 2004
Posts: 65
Location: NJ
Followers: 1

Kudos [?]: 0 [0], given: 0

i am trying to deduce it to common N or D but cannot
Director
Joined: 03 Jul 2003
Posts: 656
Followers: 2

Kudos [?]: 21 [0], given: 0

A:B:C = 7:5:9

a+b : b+c : c+a = 6:7:8
a+b+c=14 ---- (0)

Take only a+b : b+c = 6:7
or a + b / b + c = 6 /7
substitute, 14-a-b for "c" in the above equation.

Get Xa+Yb=Z --- (1)

Take a+b / c+a = 6/8
substitute, 14-a-b for "c" in the above equation.
Get Pa+Qb=R ---(2)

From (1) and (2) solve for "a" and "b"
Substitute in eqn (0) and solve for "c"

Now we have all three values.
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# ps

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