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ps algebra [#permalink] New post 06 Nov 2007, 10:47
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how can i solve this ?

If x, y, and z are positive integers and 3x = 4y = 7z, then the least possible value of x + y + z is
(A) 33
(B) 40
(C) 49
(D) 61
(E) 84
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 [#permalink] New post 06 Nov 2007, 12:01
Agree with sportyrizwan , my logic is false !

Good job - sportyrizwan.

:)

Last edited by KillerSquirrel on 06 Nov 2007, 12:23, edited 1 time in total.
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 [#permalink] New post 06 Nov 2007, 12:01
Is the OA 61

For 3x = 4y = 7z

For the least value of x,y,and z each of the three term 3x , 4y and 7z should be equal to 4*3*7
3x = 4*3*7
x = 28

Similarly
y = 21
&
z = 12

Therefore 28+21+12 = 61

What do others say
  [#permalink] 06 Nov 2007, 12:01
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