PS: Algebra : PS Archive
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# PS: Algebra

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Manager
Joined: 05 Feb 2007
Posts: 140
Followers: 1

Kudos [?]: 8 [0], given: 7

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13 May 2008, 03:25
00:00

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Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

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This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Here's another...try solving without picking numbers and show your work!

n+5 n+3
---- - ---- = 16
n-3 n-5

then n = ?

A. -4
B. -2
C. 2
D. 4
E. 6
Intern
Joined: 14 Sep 2006
Posts: 1
Followers: 0

Kudos [?]: 0 [0], given: 0

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13 May 2008, 04:00
(n+5)/(n-3) - (n+3)/(n-5) = ((n+5)*(n-5)-(n+3)*(n-3))/((n-3)*(n-5)) = -16/((n-3)*(n-5))
=> (n-3)*(n-5) = -1, only when n=4.
Re: PS: Algebra   [#permalink] 13 May 2008, 04:00
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