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Intern
Joined: 07 Sep 2008
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06 Oct 2008, 15:08
00:00

Difficulty:

(N/A)

Question Stats:

100% (01:07) correct 0% (00:00) wrong based on 2 sessions

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a certain basketball team that has played 2/3 of its games has a record of 17 wins and 3 losses. What is the greatest number of the remaining games that the team can lose and still win at least 3/4 of all of its games?

ans: 4

I keep getting 5. Can you help?
Director
Joined: 23 May 2008
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06 Oct 2008, 16:40
17 wins 3 losses =20 games

2/3x=20, x=30

3/4*30=22.5/30

cant lose .5 games so 23/30 is maximum losses

so can lose up to 7 games, already lost 3, that leaves 4 left
VP
Joined: 18 May 2008
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06 Oct 2008, 17:44
I think this has been discussed earlier.
Games played till now=17+3=20. this is 2/3 of total games
So total games to be played=3/2*20=30
Condition is winning at least 3/4 of all games 3/4 *30 is 21 (at least)[ games already won=17 so left for winning =21-17=4

quote="andreasonlinegr"]a certain basketball team that has played 2/3 of its games has a record of 17 wins and 3 losses. What is the greatest number of the remaining games that the team can lose and still win at least 3/4 of all of its games?

ans: 4

I keep getting 5. Can you help?[/quote]
Intern
Joined: 07 Sep 2008
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07 Oct 2008, 06:58
thank you !!
I got a multiplication wrong that's why I got it wrong.

Thank you again !!
Manager
Joined: 25 May 2011
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02 Nov 2011, 13:30
We should consider 23 instead of 22.5 for the games that players should win.

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