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Re: PS Co-ordinate Geo (Warning: GMATPrep) [#permalink]
Here's how I did it:
The two lines are perpendicular => they have inverse negative slope of each other -1/sqrt3 and sqrt3.

We know (t-0)/(s-0) = sqrt 3 (from slope formula using line to the origin)
=> t =(sqrt3)s
and t^2 +s^2 = 4 (length of the radius)

=> t^2 +3t^2 = 4

t = 1
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Re: PS Co-ordinate Geo (Warning: GMATPrep) [#permalink]
Thanks doc. Slope didnt strike me. Nice idea.
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Re: PS Co-ordinate Geo (Warning: GMATPrep) [#permalink]
What do you guys think of this method.
Use pythagorean theorem to find that the left hypotenuse is =2. This is also the radius.

Since its a 1, sqrt(3), 2 triangle then the angles are 30,60, 90.

So the angle next to the 90degree has to be 30deg. Therefore the angle at the right side has to be 60.

now if you look at the right side you now have a 30,60,90 triangle and the hypotenuse is 2 and therefore x has to equal 1.

so answer =1



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