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PS conundrum

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Joined: 08 May 2006
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PS conundrum [#permalink]  15 Aug 2006, 20:03
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Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
Question:
If x is the product of the positive integers from 1 to 8, inclusive, and if i, k,
m, and p are positive integers such that x = 2^i 3^k 5^m 7^p, then i + k + m + p =

A. 4
B. 7
C. 8
D.11
E. 12
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Joined: 25 Jul 2006
Posts: 100
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D

1*2*3*2^2*5*(2*3)*7*2^3

= 2^7*3^2*5^1*7^1

7+2+1+1 =11

OA?
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