christoph wrote:

banerjeea_98 wrote:

"A"

draw a perpendicular from the center to the line....distance from the center to the line is: 3/sqrt(25/16) = 12/5

min distance = 12/5 - radius of circle = 12/5 -1 = 7/5 = 1.4

baner, it seems to me that you know for almost every problem the right formula.

do you have a list of formulas ?

Altho I don't have a list, but I think in GMAT coordinate geometry, u need to know only three formulas.

1. Finding the slope of a line with two points (x1,y1) (x2,y2) =

(y2-y1)/(x2-x1)

2. Distance of a point (x1,y1) from a line (ax+by+c = 0) :

(ax1+by1+c)/sqrt(a^2+b^2)

3. Distance between two points = sqrt{(x1-x2)^2 + (y1-y2)^2}