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# ps distance word problems

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Manager
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ps distance word problems [#permalink]  18 Jun 2006, 16:36
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plz help need on the following :
A motorcycle traveling at 60 miles per hour overtakes a car traveling at 30 miles per hour that had a three-hour
head start. How far from the starting point are the two vehicles?

my approach on this one is
given T the time the motocycle is driving

60 t= 30 ( T+3) is this correct ?

THANKS
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Director
Joined: 16 Aug 2005
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Setup equations based on how far the motorcycle and the car travelled in x amount of time. The distance travelled should be equal.
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The similar thing between the two is distance.

Let the time travelled by car be x hours.

Then distance travelled by the car = d = 30x
And ditance travelled by the bike = d = 60(x-3) = 60x - 180

Now we can equate:

30x = 60x - 180
180 = 30x
x = 180/30 = 6 miles
Senior Manager
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Re: ps distance word problems [#permalink]  19 Jun 2006, 00:20
mand-y wrote:
:) plz help need on the following :
A motorcycle traveling at 60 miles per hour overtakes a car traveling at 30 miles per hour that had a three-hour
head start. How far from the starting point are the two vehicles?

my approach on this one is
given T the time the motocycle is driving

60 t= 30 ( T+3) is this correct ?

THANKS

t=3
d=60*3 = 180 miles
Manager
Joined: 05 Oct 2005
Posts: 200
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THANKS for ur explanations
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when there is a will there is a way

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Director
Joined: 07 Jun 2006
Posts: 513
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Yup. 180. Similar to another prpoblem today. The thing to remember is to think as "they meet after 't' time"

so A would have travelled 30*3 + 30t = 90+30t and B 60t

so 90+30t = 60t => t = 3 => distance = st = 60*3 = 180 miles.
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# ps distance word problems

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