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PS: Exponents

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PS: Exponents [#permalink] New post 26 Oct 2003, 02:47
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I will appreciate someone's help with this question.

3^6x=8100

x=?

Thanks,
Khurram
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 [#permalink] New post 29 Oct 2003, 04:19
your writing is more than ambiguous

do you mean 3^(6x)=8100?
if yes, then x is difficult to find. It could be found via logariphming.

if you mean (3^6)x=8100, then x=100/3^2=100/9=11 and 1/9
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 [#permalink] New post 29 Oct 2003, 08:34
its (3)^6x = 8100.How can it be solved without logarthims?anybody
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 [#permalink] New post 29 Oct 2003, 11:04
It is 3^(6x) = 8100. Sorry, couldn't make the statement clear earlier.

Is there a way to sovle it without logarithms?

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 [#permalink] New post 01 Nov 2003, 03:42
Not really.

If you had a problem like this:

3^(6x) = 531441, you could solve as follows:

3^(6x) = (3^x)^6 = 531441 = 9^6

=> 3^x = 9

x = 2

However, the 6th root of 8100 is not a power of 3 so IMO this problem cannot be solved without logrithms or some other form of non=GMAT math.
_________________

Best,

AkamaiBrah
Former Senior Instructor, Manhattan GMAT and VeritasPrep
Vice President, Midtown NYC Investment Bank, Structured Finance IT
MFE, Haas School of Business, UC Berkeley, Class of 2005
MBA, Anderson School of Management, UCLA, Class of 1993

  [#permalink] 01 Nov 2003, 03:42
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