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# PS: Exponents

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Intern
Joined: 09 Sep 2003
Posts: 3
Location: UAE
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PS: Exponents [#permalink]  26 Oct 2003, 02:47
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
I will appreciate someone's help with this question.

3^6x=8100

x=?

Thanks,
Khurram
SVP
Joined: 03 Feb 2003
Posts: 1609
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your writing is more than ambiguous

do you mean 3^(6x)=8100?
if yes, then x is difficult to find. It could be found via logariphming.

if you mean (3^6)x=8100, then x=100/3^2=100/9=11 and 1/9
Intern
Joined: 13 Sep 2003
Posts: 43
Location: US
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Kudos [?]: 7 [0], given: 0

its (3)^6x = 8100.How can it be solved without logarthims?anybody
Intern
Joined: 09 Sep 2003
Posts: 3
Location: UAE
Followers: 0

Kudos [?]: 0 [0], given: 0

It is 3^(6x) = 8100. Sorry, couldn't make the statement clear earlier.

Is there a way to sovle it without logarithms?

Thanks.
GMAT Instructor
Joined: 07 Jul 2003
Posts: 770
Location: New York NY 10024
Schools: Haas, MFE; Anderson, MBA; USC, MSEE
Followers: 13

Kudos [?]: 52 [0], given: 0

Not really.

If you had a problem like this:

3^(6x) = 531441, you could solve as follows:

3^(6x) = (3^x)^6 = 531441 = 9^6

=> 3^x = 9

x = 2

However, the 6th root of 8100 is not a power of 3 so IMO this problem cannot be solved without logrithms or some other form of non=GMAT math.
_________________

Best,

AkamaiBrah
Former Senior Instructor, Manhattan GMAT and VeritasPrep
Vice President, Midtown NYC Investment Bank, Structured Finance IT
MFE, Haas School of Business, UC Berkeley, Class of 2005
MBA, Anderson School of Management, UCLA, Class of 1993

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