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Re: PS -GMATprep -circle [#permalink]
22 Jun 2008, 18:36

goalsnr wrote:

Ok i figured it out .

I 'll wait for sometime before I post my explanation incase others want to try.

I think as a general rule, when the lines are of the same length (radius in this case) and they are perpendicular to each other ...... they are mirror images of each other and their co-ordinates are merely interchanged hence (-sqrt3, 1) would become (1,sqrt3).

If you have a better explanation i would love to know it !!

Re: PS -GMATprep -circle [#permalink]
23 Jun 2008, 16:10

saurabhkowley18 wrote:

goalsnr wrote:

Ok i figured it out .

I 'll wait for sometime before I post my explanation incase others want to try.

I think as a general rule, when the lines are of the same length (radius in this case) and they are perpendicular to each other ...... they are mirror images of each other and their co-ordinates are merely interchanged hence (-sqrt3, 1) would become (1,sqrt3).

If you have a better explanation i would love to know it !!

:D thats the trap I fell for. There is a classic parabola question using the mirror image and I thought this question was on the similar lines.

Re: PS -GMATprep -circle [#permalink]
23 Jun 2008, 17:42

so i just learned this trick the other day...if you have two lines intersecting to form a righ-angle triangle..you can simply use the formula, slope Line1*slope Line2=-1..

basing that slope of line 1 is -sqrt(3)/1*1/sqrt(3)..means s=1..

Re: PS -GMATprep -circle [#permalink]
23 Jun 2008, 19:57

if 2 lines are perpendicular to each other the product of their slopes is -1 ->m1= -1/m2 if 2 lines are parallel to each other the product of their slopes are equal ->m1=m2

gmatclubot

Re: PS -GMATprep -circle
[#permalink]
23 Jun 2008, 19:57

Great to know you are joining Kellogg. A lot was being talked about your last minute interview on Pagalguy (all good though). It was kinda surprise that you got the...