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# PS - Integers and divisors

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PS - Integers and divisors [#permalink]  27 Oct 2010, 21:19
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Question Stats:

76% (02:15) correct 23% (00:56) wrong based on 2 sessions
For how many different positive integers n is a divisor of n^3+8?
A - None
B - One
C - Two
D - Three
E - Four

Thank you!
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Posts: 11594
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Kudos [?]: 9588 [0], given: 826

Re: PS - Integers and divisors [#permalink]  27 Oct 2010, 21:25
vivaslluis wrote:
For how many different positive integers n is a divisor of n^3+8?
A - None
B - One
C - Two
D - Three
E - Four

Thank you!

The question asks for how many different positive integers n, n^3+8 is divisible by n.

Well the first term n^3 is divisible by n, the second term, 8, to be divisible by n it should be a factor of 8. 8=2^3 hence it has 3+1=4 factors: 1, 2, 4, and 8 so n^3+8 is divisible by n for 4 values: 1, 2, 4, and 8.

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Re: PS - Integers and divisors   [#permalink] 27 Oct 2010, 21:25
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# PS - Integers and divisors

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