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# PS: Medals

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Manager
Joined: 01 Mar 2009
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PS: Medals [#permalink]  16 Apr 2009, 16:10
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Question Stats:

100% (01:39) correct 0% (00:00) wrong based on 0 sessions
Just not understanding the OA. A very simple question however I got it wrong.

Medals are to be awarded to three teams in a 10-team competition. If one medal is gold, one medal is silver, and one medal is bronze, how many different ways are there to award the three medals to teams in the competition?

A) 10!/7!
B) 10!/3!7!
C) 10!/3!
D) 7!/3!
E) 7!/4!3!
Intern
Joined: 09 Apr 2009
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Re: PS: Medals [#permalink]  16 Apr 2009, 16:39
A.

Permutations formula..n!/(n-k)! n=10, k=3

Or simply: 10 teams to choose from for gold, 9 for silver, 8 for bronze so 10*9*8, which is 10!/7!
Manager
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Re: PS: Medals [#permalink]  16 Apr 2009, 18:31
Thanks
I figured out what my problem is...forgot about the concept of sequence.
Director
Joined: 01 Apr 2008
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Schools: IIM Lucknow (IPMX) - Class of 2014
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Re: PS: Medals [#permalink]  22 Apr 2009, 05:46
Simple but basic problem to understand combination vs permutation

Since medals are distinct >> order matters >> use permutation.

If medals are not distinct >> order does not matter >> use combination.
Re: PS: Medals   [#permalink] 22 Apr 2009, 05:46
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