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# PS: MODUL+FACTORIAL-5

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SVP
Joined: 03 Feb 2003
Posts: 1608
Followers: 6

Kudos [?]: 76 [0], given: 0

PS: MODUL+FACTORIAL-5 [#permalink]  20 Jun 2003, 11:38
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
For working on mistakes. This is a tough one. Post yous approach; I want to take a look.

|2Z+1|=|Z|!
SVP
Joined: 03 Feb 2003
Posts: 1608
Followers: 6

Kudos [?]: 76 [0], given: 0

you are too weak to crash it
Manager
Joined: 18 Jun 2003
Posts: 141
Location: Hockeytown
Followers: 2

Kudos [?]: 16 [0], given: 0

x = {0, -1}

No approach, really, just started with zero, looked at +/- integers until L and R sides of equation evidence divergence
Manager
Joined: 24 Jun 2003
Posts: 146
Location: India
Followers: 1

Kudos [?]: 1 [0], given: 0

PS: MODUL+FACTORIAL-5 [#permalink]  26 Jun 2003, 04:48
The LHS would always be an odd number and the RHS would always be an even number except when Z=0 or -1. Therefore these are the only two solution values for this equation
PS: MODUL+FACTORIAL-5   [#permalink] 26 Jun 2003, 04:48
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