PS numbers : GMAT Problem Solving (PS)
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# PS numbers

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09 May 2011, 07:05
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What is thte total number of different 5-digit integers that contain all of the digits 2,5,4,3,7 and which both the units digit and the thousands digit are odd integers?

a.10 b.8 c.36 d.24 e.12
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09 May 2011, 07:43
As all the digits have to be present in the number hence repetition is not allowed such as 22222 or 33333 and so on.

Thousands and Units place can be taken by 3,5,7 meaning 3*2 ways = 6

Remaining positions can be taken by 2,4 and the remaining Odd digit - 3! ways = 6

thus total ways = 6*6 = 36.
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09 May 2011, 12:51
First arrange odd numbers in units and thousand digit.

This can be done in 3*2 ways(as we have 3 odd numbers)

Rest of 3 digits can be arranged in 3! ways.

Total possible arrangements = 3*2*3! =36

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10 May 2011, 05:17
3P2 * 3P3

= 3!/1! * 3!/0!

= 36

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Re: PS numbers   [#permalink] 10 May 2011, 05:17
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