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PS-Numbers

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Senior Manager
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PS-Numbers [#permalink] New post 07 Dec 2008, 06:33
00:00
A
B
C
D
E

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(N/A)

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0% (00:00) correct 0% (00:00) wrong based on 0 sessions
A set of numbers has the property that for any number t in the set, t + 2 is in the set. If –1 is in the set, which of the following must also be in the set?
I. –3 II. 1 III. 5
A. I only
B. II only
C. I and II only
D. II and III only
E. I, II, and III
Senior Manager
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Re: PS-Numbers [#permalink] New post 07 Dec 2008, 08:22
I go with E.

Set T will be containing the numbers {....-5,-3,-1,1,3,5,.....}
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Re: PS-Numbers [#permalink] New post 07 Dec 2008, 08:33
Once again, little confusing . The statement says for any t, t+2 should be in the set, it does not say for any t+2, t should be in the set. For that reasons, i would go for 1 and 5 to be in the set, Hence answer should be D.

Pls post the QA soon vivektripathi, i would like to know of this is the right thinking ....
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Re: PS-Numbers [#permalink] New post 07 Dec 2008, 12:07
I go with D as well.

The question asks which numbers MUST be there. -1 could be the 'root' of the series, which would mean -3 doesnt necessarily have to be there.

Another way of looking at it is the series has t and t+2 for all t, but not t-2 necessarily.

whats the OA?
Re: PS-Numbers   [#permalink] 07 Dec 2008, 12:07
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