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PS OG 11th, 159

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Intern
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PS OG 11th, 159 [#permalink] New post 04 Dec 2007, 11:21
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Hi all,

Can anyone explain an easy way how to solve this one?

If the product of the integers w, x, y and z is 770, and if 1<w<x<y<z, what is the value of w+z ?

A 10
B 13
C 16
D 18
E 21

Thanks..
Manager
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Re: PS OG 11th, 159 [#permalink] New post 04 Dec 2007, 11:25
Crow wrote:
Hi all,

Can anyone explain an easy way how to solve this one?

If the product of the integers w, x, y and z is 770, and if 1<w<x<y<z, what is the value of w+z ?

A 10
B 13
C 16
D 18
E 21

Thanks..


factor 770: 77*10=7*11*5*2, then put them in order 2 5 7 11, so w=2 and z=11, and w+z=13
Intern
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 [#permalink] New post 04 Dec 2007, 11:32
iish..

i tried to factor as well, but kept getting the wrong factors...
now i realized that for me 770/2 = 350 :lol:

its been a long day..

thanks elgo!

OA is B
Manager
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Joined: 11 Aug 2007
Posts: 65
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 [#permalink] New post 04 Dec 2007, 11:40
Crow wrote:
iish..

i tried to factor as well, but kept getting the wrong factors...
now i realized that for me 770/2 = 350 :lol:

its been a long day..

thanks elgo!

OA is B


completely understand you, that happens to me VERY often:)
  [#permalink] 04 Dec 2007, 11:40
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PS OG 11th, 159

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