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# PS OG 11th, 159

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Intern
Joined: 23 Sep 2007
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PS OG 11th, 159 [#permalink]  04 Dec 2007, 11:21
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Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
Hi all,

Can anyone explain an easy way how to solve this one?

If the product of the integers w, x, y and z is 770, and if 1<w<x<y<z, what is the value of w+z ?

A 10
B 13
C 16
D 18
E 21

Thanks..
Manager
Joined: 11 Aug 2007
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Kudos [?]: 10 [0], given: 0

Re: PS OG 11th, 159 [#permalink]  04 Dec 2007, 11:25
Crow wrote:
Hi all,

Can anyone explain an easy way how to solve this one?

If the product of the integers w, x, y and z is 770, and if 1<w<x<y<z, what is the value of w+z ?

A 10
B 13
C 16
D 18
E 21

Thanks..

factor 770: 77*10=7*11*5*2, then put them in order 2 5 7 11, so w=2 and z=11, and w+z=13
Intern
Joined: 23 Sep 2007
Posts: 18
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iish..

i tried to factor as well, but kept getting the wrong factors...
now i realized that for me 770/2 = 350

its been a long day..

thanks elgo!

OA is B
Manager
Joined: 11 Aug 2007
Posts: 64
Followers: 1

Kudos [?]: 10 [0], given: 0

Crow wrote:
iish..

i tried to factor as well, but kept getting the wrong factors...
now i realized that for me 770/2 = 350

its been a long day..

thanks elgo!

OA is B

completely understand you, that happens to me VERY often:)
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