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PS og 79 number of multiples

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PS og 79 number of multiples [#permalink] New post 24 Nov 2005, 02:13
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:) hello
How many multiples of 4 are there between 12 and 96 inclusive ?
21
22
23
24
25


96 - 12= 84
84 /4 = 21
21 + 1 Since inclusive = 22

is it the right way to proceed ?
thanks
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Re: PS og 79 number of multiples [#permalink] New post 24 Nov 2005, 05:07
Another way to solve this problem is to recognise that this is an AP.
and the series is 12,16,...,96. The first term is 12, second is 16, and difference is 4. We need to find which term of the series is 96.
To find the nth term of a series we can use
tn = a + (n-1) d
96 = 12 + (n-1)4
96 = 12 + 4n -4
=> 4n = 88 n = 22
Re: PS og 79 number of multiples   [#permalink] 24 Nov 2005, 05:07
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