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PS Pairs [#permalink] New post 15 Nov 2007, 02:23
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There are 4 guys, 2 girls and 14 dogs. How many dog-boys pairs are possible.
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Re: PS Pairs [#permalink] New post 15 Nov 2007, 06:16
bmwhype2 wrote:
There are 4 guys, 2 girls and 14 dogs. How many dog-boys pairs are possible.


I'm terrible at these questions but my guess is 56. 1 boy can be paired with 14 dogs. So for 4 boys we will have 4*14 = 56 dog boy pairs...??
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 [#permalink] New post 15 Nov 2007, 06:47
I am not good in this, but I will just give my logic.

We have 4 boys and 14 dogs. So if we were to pair them, the 1st boy can pair with any of the 14 dogs, so 14 right.

2nd boy can have 13 ways, since 1 dog has already been paired

3rd boy 12

4th boy 11

Now is the part I am not sure of, is it "or" or "and" which determines whether we need to add or multiply them, I am going with "and" so I get 24,024.

If "or" then 50?
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 [#permalink] New post 15 Nov 2007, 07:00
Different possible dog-boy pairs are 56 (4*14). but if the question says that how many dog-boy pairs are possible, when total number of boys are 4 and total number of dogs are 14, then the answer will be 4. i.e. equal to the number of boys.

what are the options?

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 [#permalink] New post 01 Dec 2007, 21:05
Expert's post
14P4=14*13*12*11.

but maybe 14^4 ?

what is OA?
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Re: [#permalink] New post 08 Jan 2008, 21:46
walker wrote:
14P4=14*13*12*11.

but maybe 14^4 ?

what is OA?


why use perms in this case? maybe because if we have 4 boys to be paired, then we have to choose 4 dogs out of the 14 available....so 14P4....this is if the choiche of all the pairs is istantaneous...otherwise I think that simply 14*4 is good. anyway, what is OA? what is the right reasoning?
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Re: PS Pairs [#permalink] New post 09 Jan 2008, 05:45
bmwhype2 wrote:
14*4

simple combo question


Simple, but give some explaination
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Re: PS Pairs [#permalink] New post 09 Jan 2008, 05:58
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sondenso wrote:
bmwhype2 wrote:
14*4

simple combo question


Simple, but give some explaination


There are 4 boys to choose from and 14 dogs to choose from 4*14 = 56 possible pairs

This is the definition of a basic combo question. You guys are just so used to doing uber-high level math you tried to make it more complicated than it really is :-D

EDIT: since they're being put into pairs of 2 you can write it 4C1*14C1 = 56.

Last edited by eschn3am on 09 Jan 2008, 07:04, edited 1 time in total.
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Re: PS Pairs [#permalink] New post 09 Jan 2008, 07:05
bmwhype2 wrote:
There are 4 guys, 2 girls and 14 dogs. How many dog-boys pairs are possible.


This is a great problem because most of us are so use to complicated combinatorics questions we often miss that its simply

4*14.

Here is a question from a wonderlic test (test used to draft NFL players) that is similar to this problem:

Randolph has 8 ties, 6 pairs of pants, and 4 dress shirts. How many days could he possibly go without wearing the same combination of these three items.

On the wonderlic test you have about 15-30sec to answer this question.
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Re: PS Pairs [#permalink] New post 09 Jan 2008, 07:17
sondenso wrote:
bmwhype2 wrote:
14*4

simple combo question


Simple, but give some explaination

the other group is extraneous info.
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Re: PS Pairs [#permalink] New post 28 Sep 2009, 03:08
Yes.. It is 4 * 14.. 56 ways..
Re: PS Pairs   [#permalink] 28 Sep 2009, 03:08
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