|
Author |
Message |
|
Manager
Joined: 23 Oct 2010
Posts: 93
Location: India
Followers: 2
Kudos [?]:
15
[0], given: 6
|
Re: PS Population (m01q09) [#permalink]
 25 Nov 2010, 04:56
B. Pop growth rate = 4800 - 1200 / 3600 = 1/3 1996 pop = 4800 + 4800*1/3 = 6400 Posted from my mobile device 
|
|
|
|
|
|
|
|
|
Manager
Joined: 19 Oct 2010
Posts: 242
Location: India
Concentration: Marketing, Finance
GMAT 1: 560 Q36 V31
GPA: 3
Followers: 5
Kudos [?]:
10
[0], given: 21
|
Re: PS Population (m01q09) [#permalink]
09 Jan 2011, 09:51
This was my method: The increase from 1990 to 1993 was 1200. Therefore when expressed as a percentage it comes to about 33.33% which is really 33.33/100. If this were converted to per thousand, it would be 333 per thousand. From there on, [4800 + 4800(333.3/1000)] to find the increase.
_________________
petrifiedbutstanding
|
|
|
|
|
|
Manager
Joined: 21 Nov 2010
Posts: 141
Followers: 0
Kudos [?]:
2
[0], given: 12
|
x2suresh wrote: good discussion guys.
You view the question in differt way to..
You can rephrase the original problem "% increase is constant over the periods"
% increase inpopulation from 1990-1993 = % increase in population from 1993-96
(4800-3600)/3600 = 33.3%
1996 population = 4800 *1.333 = 6400 Your response makes sense. I'm not sure how close this is to a GMAT question.
|
|
|
|
|
|
Manager
Joined: 10 Jan 2011
Posts: 238
Location: India
GMAT Date: 07-16-2012
GPA: 3.4
WE: Consulting (Consulting)
Followers: 0
Kudos [?]:
24
[0], given: 20
|
Re: PS Population (m01q09) [#permalink]
02 Dec 2011, 00:19
This is really good question, and very good discussion regarding wording of the Q
_________________
-------Analyze why option A in SC wrong-------
|
|
|
|
|
|
Intern
Joined: 29 Nov 2012
Posts: 7
GMAT 1: Q50 V41
Followers: 0
Kudos [?]:
1
[0], given: 1
|
Re: PS Population (m01q09) [#permalink]
30 Nov 2012, 12:17
Like you, I have a problem with this question, but because of wording. It is fine for the question to ask constant growth rate, but it cannot be ambiguous about base years, which is what it did. For instance, what was the population in 1991 or 1992? it isn't 11% (33%/3) year over year, because that ignores the compounding error that will result. By neglecting to specify that the base interval was 3 years, it falsely implies that the rate of pop. growth is YoY, when an answer like 6400 shows clearly that it is not. To compute YoY and go from 3600 to 4800 over 3 years: 3600(1+growthrate)^3=4800. Then dividing both sides by 3600 yields (1+growthrate)^3=(4/3). We don't have the calculating tools on the GMAT to compute logs and thus it is an unfair question.
|
|
|
|
|
|
Intern
Joined: 10 Mar 2013
Posts: 10
Followers: 0
Kudos [?]:
-25
[0], given: 1
|
Re: PS Population (m01q09) [#permalink]
12 Mar 2013, 05:27
(A) 6,000
(B) 6,400
(C) 7,200
(D) 8,000
(E) 9,600
percentage growth of population from 90 to 93 = 33.33 %.
percentage growth of population from 93 to 96 = 33.33 %
Simply add 33% of the population in 93 to 4800
ans = 4800+ 33.33% of 4800 =6400
|
|
|
|
|
|
|
Re: PS Population (m01q09)
[#permalink]
12 Mar 2013, 05:27
|
|
|
|
|
|
|
|
|
|
|
close
