PS (potatoes) - m04q05 : Retired Discussions [Locked] - Page 2
Check GMAT Club Decision Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 23 Jan 2017, 15:52

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# PS (potatoes) - m04q05

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
Manager
Joined: 15 Aug 2012
Posts: 111
Location: India
Concentration: Technology, Strategy
Schools: Merage '15 (A)
GPA: 3.6
WE: Consulting (Computer Software)
Followers: 6

Kudos [?]: 47 [0], given: 22

Re: PS (potatoes) - m04q05 [#permalink]

### Show Tags

18 Apr 2013, 00:30
Robert can eat a 20 kg. bag of potatoes in 10 days. He and his wife Jane can eat the same bag in 7 days. How many days does it take Jane to eat a 20 kg. bag of potatoes by herself?

Let Jane eat 20kg bag of potatoes in x days.

The eqn=>1/x + 1/10 = 1/7

solving for x we get 70/3.

Hence B
Intern
Joined: 24 Feb 2014
Posts: 6
Schools: ISB
Followers: 0

Kudos [?]: 2 [0], given: 21

Re: PS (potatoes) - m04q05 [#permalink]

### Show Tags

19 Mar 2014, 19:13
Vercules wrote:
Policarpa wrote:
Can someone type out the Algebra from:
(1/10) + (1/x) = 1/7

Thanks

$$\frac{1}{10}+\frac{1}{x}=\frac{1}{7}$$

$$\frac{1}{x} = \frac{1}{7}-\frac{1}{10}$$

$$\frac{1}{x}=\frac{10-7}{70}$$

$$\frac{1}{x}=\frac{3}{70}$$

$$x=\frac{70}{3}$$

Hope this helps,

Vercules

dis is the right approach for such a problem..easy n crisp! cheers!
Intern
Joined: 02 Dec 2013
Posts: 11
Location: India
Concentration: International Business, Technology
GMAT Date: 08-23-2014
GPA: 3.5
WE: Engineering (Other)
Followers: 0

Kudos [?]: 5 [0], given: 9

Re: PS (potatoes) - m04q05 [#permalink]

### Show Tags

19 Mar 2014, 23:20
If robert eats 20kg of potatoes in 10 days, then per day he ll eat 2kg of potatoes.
Let "x" be the amount of potatoes, which will be eaten by his wife., then we can write a simple equation as follows

2+x=(20/7) since its given that if both eat together then 20kgs of potatoes will be finished in 7 days

therefore,
we get x=6/7

Let n be the number of days rob's wife needs to eat 20 kg of potatoes,

(X)x(n)=20
n=20x7/6
n=70/3...... Voilaaaaa
Re: PS (potatoes) - m04q05   [#permalink] 19 Mar 2014, 23:20

Go to page   Previous    1   2   [ 23 posts ]

Similar topics Replies Last post
Similar
Topics:
2 PS 4 05 Jun 2012, 21:51
3 ps 2 27 Mar 2011, 19:26
PS: m 15 #6 1 20 Jun 2009, 11:21
PS: m 15 #31 3 20 Jun 2009, 11:05
PS: Divisors 6 25 Feb 2009, 15:19
Display posts from previous: Sort by

# PS (potatoes) - m04q05

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics

Moderator: Bunuel

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.