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Director

Joined: 03 Sep 2006

Posts: 910

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PS-prep [#permalink]

24 Jun 2007, 00:46

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Director

Joined: 09 Aug 2006

Posts: 776

Followers: 1

Kudos [?]: 18 [0], given: 0

[#permalink]

24 Jun 2007, 03:33

To minimize the number of hrs. that machine B works, we should use the maximum hours that machine A can work,i.e., 8 hours.

Work = Rate * Time

For A:
Rate = 9000 pencils/hr
Time = 8hrs
Work = 72000 pencils

Pencils that remained to be produced = 100000-72000 = 28000

For B:
Rate = 7000 pencils/hr
Work = 28000 pencils
Time = 28000/7000 = 4hrs

The answer according to me should be A. Is this correct?

[#permalink] 24 Jun 2007, 03:33

	Similar topics	Author	Replies	Last post
Similar Topics:	PS-prep	LM	1	24 Jun 2007, 00:40
	PS-prep	LM	3	24 Jun 2007, 00:45
	PS-Prep, time killer	misterJJ2u	6	28 Jun 2007, 09:19

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