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Director
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New post 24 Jun 2007, 00:46
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A
B
C
D
E

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Director
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New post 24 Jun 2007, 03:33
To minimize the number of hrs. that machine B works, we should use the maximum hours that machine A can work,i.e., 8 hours.

Work = Rate * Time

For A:
Rate = 9000 pencils/hr
Time = 8hrs
Work = 72000 pencils

Pencils that remained to be produced = 100000-72000 = 28000

For B:
Rate = 7000 pencils/hr
Work = 28000 pencils
Time = 28000/7000 = 4hrs

The answer according to me should be A. Is this correct?
  [#permalink] 24 Jun 2007, 03:33
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