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# PS-prep

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Director
Joined: 03 Sep 2006
Posts: 885
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Kudos [?]: 255 [0], given: 33

PS-prep [#permalink]  23 Jun 2007, 23:46
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Director
Joined: 09 Aug 2006
Posts: 766
Followers: 1

Kudos [?]: 68 [0], given: 0

[#permalink]  24 Jun 2007, 02:33
To minimize the number of hrs. that machine B works, we should use the maximum hours that machine A can work,i.e., 8 hours.

Work = Rate * Time

For A:
Rate = 9000 pencils/hr
Time = 8hrs
Work = 72000 pencils

Pencils that remained to be produced = 100000-72000 = 28000

For B:
Rate = 7000 pencils/hr
Work = 28000 pencils
Time = 28000/7000 = 4hrs

The answer according to me should be A. Is this correct?
[#permalink] 24 Jun 2007, 02:33
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# PS-prep

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