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PS Sandbox [#permalink] New post 09 Feb 2009, 22:54
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a carpenter constructed a rectangular sandbox with a capacity of 10 cubic feet. If the carpenter were to make a similar sandbox twice as long, twice as wide and twice as high as the first sandbox, what would be the capacity, in cubic feet, of the second sandbox?

a 20
b 40
c 60
d 80
e 100
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Re: PS Sandbox [#permalink] New post 09 Feb 2009, 23:04
bigtreezl wrote:
a carpenter constructed a rectangular sandbox with a capacity of 10 cubic feet. If the carpenter were to make a similar sandbox twice as long, twice as wide and twice as high as the first sandbox, what would be the capacity, in cubic feet, of the second sandbox?

a 20
b 40
c 60
d 80
e 100


lwh=10 ft^3

2l*2w*2h = 8*lwh = 80

D
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Director
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Re: PS Sandbox [#permalink] New post 09 Feb 2009, 23:05
x2suresh wrote:
bigtreezl wrote:
a carpenter constructed a rectangular sandbox with a capacity of 10 cubic feet. If the carpenter were to make a similar sandbox twice as long, twice as wide and twice as high as the first sandbox, what would be the capacity, in cubic feet, of the second sandbox?

a 20
b 40
c 60
d 80
e 100


lwh=10 ft^3

2l*2w*2h = 8*lwh = 80

D


better explanation than OG 11..thanks
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Re: PS Sandbox [#permalink] New post 10 Feb 2009, 00:34
volume of rectangular box=l*b*h
since each is multipleied by 2
so new volume=8 *10=80
D
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Re: PS Sandbox [#permalink] New post 10 Feb 2009, 00:47
There is a general rule for a object of any form: if we increase all linear sizes by n, all areas will increase by n^2 and all volumes will increase by n^3. So, we can apply here n^3 formula even not knowing the formula for volume. In other words, n^3 will be also true for objects of other forms, such as spheres, pyramids, ellipsoids and even tree-like objects.
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Re: PS Sandbox   [#permalink] 10 Feb 2009, 00:47
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