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PS: Set [#permalink] New post 25 Apr 2005, 19:34
00:00
A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
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 [#permalink] New post 25 Apr 2005, 20:07
re-posting question as jpeg
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 [#permalink] New post 25 Apr 2005, 20:12
now my answer ;)

Total = 100% = 60+50+35 -2x -2y-2z+10
2(x+y+z) = 55

therefore % of people buying 2 products is
x+y+z = 27.5%
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 [#permalink] New post 25 Apr 2005, 22:51
using the exact same diagram - i got ans as 25......
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 [#permalink] New post 26 Apr 2005, 01:46
I am lost on this one...I found 7.5%

60+50+35 -3*10 -2(x+y+z) = 100
145 - 30 -2(x+y+z) = 100
115 - 2(x+y+z) = 100
2(x+y+z) = 15
x+y+z = 7.5

:oops: where is the mistake..I mean in a logic view :?:
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 [#permalink] New post 26 Apr 2005, 05:24
Askg, thx for reposting. I think there are two issues with you equation

1) you didn't add back x+y+z after subtracting them
2) you didn't subtract 10 three times.

In my mind this shud be the eqn

100= 60+50+35 -2x -2y-2z-30 + x+y+z+10

x+y+z = 25%

However, OA is different. Any one else wanna try ?
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 [#permalink] New post 26 Apr 2005, 06:45
banerjeea_98 wrote:
Askg, thx for reposting. I think there are two issues with you equation

1) you didn't add back x+y+z after subtracting them
2) you didn't subtract 10 three times.

In my mind this shud be the eqn

100= 60+50+35 -2x -2y-2z-30 + x+y+z+10

x+y+z = 25%

However, OA is different. Any one else wanna try ?


yeah i goofed up :oops:

I'm getting 25% as those who bought only 2 things.

But final answer should be 35%, as those who bought 3 things would automatically buy 2 things.
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Last edited by ashkg on 26 Apr 2005, 07:01, edited 1 time in total.
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 [#permalink] New post 26 Apr 2005, 06:57
Antmavel wrote:
I am lost on this one...I found 7.5%

60+50+35 -3*10 -2(x+y+z) = 100
145 - 30 -2(x+y+z) = 100
115 - 2(x+y+z) = 100
2(x+y+z) = 15
x+y+z = 7.5

:oops: where is the mistake..I mean in a logic view :?:


after subtracting all the x y z components totally, you will need to add it once.

The above equations basically come from something like this ( add all the spaces in the circles )

100 = (60-x-y-10) + (50-z-y-10) + (35-x-z-10) + x + y + z + 10
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 [#permalink] New post 26 Apr 2005, 12:37
ashkg wrote:
Antmavel wrote:
I am lost on this one...I found 7.5%

60+50+35 -3*10 -2(x+y+z) = 100
145 - 30 -2(x+y+z) = 100
115 - 2(x+y+z) = 100
2(x+y+z) = 15
x+y+z = 7.5

:oops: where is the mistake..I mean in a logic view :?:


after subtracting all the x y z components totally, you will need to add it once.

The above equations basically come from something like this ( add all the spaces in the circles )

100 = (60-x-y-10) + (50-z-y-10) + (35-x-z-10) + x + y + z + 10


can you not just say,
100%=A+B+C-AB-BC-CA+2ABC?
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 [#permalink] New post 26 Apr 2005, 13:00
ashkg wrote:
yeah i goofed up :oops: I'm getting 25% as those who bought only 2 things. But final answer should be 35%, as those who bought 3 things would automatically buy 2 things.


however, the question is ambigous, therefore i think both should be correct.

mirhaque wrote:
can you not just say, 100%=A+B+C-AB-BC-CA+2ABC?

its the same thing like kale kami or kami kale. :wink:
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 [#permalink] New post 26 Apr 2005, 13:15
OA is 15%....just wanted to confirm that it is definitely wrong, there was no choice for 35%...so I chose 25%, which we all agree on...thx guys.
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 [#permalink] New post 26 Apr 2005, 20:17
If the Question is asking for customers who bought exactly 2 things:

60-(x+y+10) + 50-(x+z+10)+35-(y+z+10)+x-10+y-10+z-10 = 100

x+y+z = 15
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 [#permalink] New post 27 Apr 2005, 05:18
prep_gmat wrote:
If the Question is asking for customers who bought exactly 2 things:

60-(x+y+10) + 50-(x+z+10)+35-(y+z+10)+x-10+y-10+z-10 = 100

x+y+z = 15


you are subtracting 10% six times. I don't think that is correct. If we refer to askg's venn diagram, the eqn shoould be:

100= (60-x-y-10)+(50-y-z-10)+(35-x-z-10) + x+y+z+10

x+y+z = 25%
  [#permalink] 27 Apr 2005, 05:18
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