PS - Set theory : PS Archive
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PS - Set theory

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Senior Manager
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28 May 2006, 08:31
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Table

Last edited by gmat_crack on 07 Jul 2008, 19:55, edited 1 time in total.
Senior Manager
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Re: PS - Set theory [#permalink]

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28 May 2006, 09:31
guptaraja wrote:
gmat_crack wrote:
Table

Factor Percent of Respondents

User-friendly 56%

Fast response time 48%

Bargain prices 42%

The table gives three factors to be considered when choosing an Internet service provider and the percent of the 1,200 respondents to a survey who cited that factor as important. If 30 percent of the respondents cited both "user-friendly" and "fast response time," what is the maximum possible number of respondents who cited "bargain prices," but neither "user-friendly" nor "fast response time?"
A. 312
B. 336
C. 360
D. 384
E. 420

A

100 - (56 + 48 - 30) = 26%
26 * 12 = 312

Can u explain why you selected only two group of users?
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Joined: 05 Apr 2006
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Re: PS - Set theory [#permalink]

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28 May 2006, 15:51
We need to maximize one type of users which are not the other two type of users . so just add these two and subtract the overlapping users.
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Re: PS - Set theory [#permalink]

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24 Apr 2008, 09:51
Total = U + B + F - (UF + UB + BF) - 2*(BUF)

1200 = 56*12 + 48*12 + 42*12 - 30*12 - [(UB + BF) + 2 * (BUF)]

[(UB + BF) + 2 * (BUF)] = 56*12 + 48*12 + 42*12 - 30*12 - 1200

Let's make life easy and call [(UB + BF) + 2 * (BUF)] = x

x = 192

We need: B - [(UB + BF) + 2 * (BUF)] - Draw circle for better understanding

42*12 - 192 = 312
Re: PS - Set theory   [#permalink] 24 Apr 2008, 09:51
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