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PS: simple equation

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SVP
Joined: 03 Feb 2003
Posts: 1613
Followers: 6

Kudos [?]: 58 [0], given: 0

PS: simple equation [#permalink]  02 Jul 2004, 00:01
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
||Z|–2|=1
SVP
Joined: 03 Feb 2003
Posts: 1613
Followers: 6

Kudos [?]: 58 [0], given: 0

do you have a solution or guess them?
remember that modul equtions sometimes have more roots than they seem to have, other times less.
Intern
Joined: 26 Jan 2003
Posts: 28
Location: Reality
Followers: 1

Kudos [?]: 0 [0], given: 0

stolyar wrote:
do you have a solution or guess them?
remember that modul equtions sometimes have more roots than they seem to have, other times less.

Do you mean by this that there are more or less than 4 roots or you are just trying to encourage us to solve instead of guessing.
_________________

SVP
Joined: 03 Feb 2003
Posts: 1613
Followers: 6

Kudos [?]: 58 [0], given: 0

stolyar wrote:
do you have a solution or guess them?
remember that modul equtions sometimes have more roots than they seem to have, other times less.

Do you mean by this that there are more or less than 4 roots or you are just trying to encourage us to solve instead of guessing.

Your answers are correct; however, guessing can be dangerous while dealing with absolute values.
Intern
Joined: 26 Jan 2003
Posts: 28
Location: Reality
Followers: 1

Kudos [?]: 0 [0], given: 0

stolyar wrote:
stolyar wrote:
do you have a solution or guess them?
remember that modul equtions sometimes have more roots than they seem to have, other times less.

Do you mean by this that there are more or less than 4 roots or you are just trying to encourage us to solve instead of guessing.

Your answers are correct; however, guessing can be dangerous while dealing with absolute values.

I actually solved it, though i solve in mind and than get an answer.
_________________

SVP
Joined: 01 May 2006
Posts: 1813
Followers: 8

Kudos [?]: 92 [0], given: 0

||Z|â€“2|= 1

We obtain 2 equations:
> |Z|â€“2 = 1
or
> -(|Z|â€“2)= 1

Thus,
> |Z| = 3
or
> |Z| = 1

Finally, we obtain the 4 solutions for z : {-3, -1, 1, 3}
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