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ps - sum + sum ?

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VP
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ps - sum + sum ? [#permalink] New post 20 Oct 2005, 11:31
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A
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Question Stats:

100% (02:30) correct 0% (00:00) wrong based on 0 sessions
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Manager
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 [#permalink] New post 20 Oct 2005, 12:00
BbBbBBBBBbBBbBbBBb.....

let q be sum of integers from 75 to 150
so p must simply be q + 151

1/q + 1/(q+151) ... rearrange and you get

2q + 151 / q^2 + q151
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 [#permalink] New post 20 Oct 2005, 12:00
LCM is q^2-151q

then q-151 goes into LCM q-151 times, and q goes q+151

so you have (q-151+q+151)/(q^2-151q)=2q/(q^2-151q)
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 [#permalink] New post 20 Oct 2005, 12:08
hehe I did this one again and now get a different result... letting q be the sum of integers..... I let p be q-151...

but then I get A....:S
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 [#permalink] New post 20 Oct 2005, 18:54
Good one....

Q= p+151 so p=q-151

now solve 1/q-151 + 1/q ..... you will get A
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 [#permalink] New post 20 Oct 2005, 19:21
A.

p= sum (75+76+77+............+150)
q= sum (75+76+77+............150+151)
q= sum (75+76+77+............150) +151
q= p+151
p= q-151

given that: 1/p+1/q = ?
= (p+q)/(pq)
replace p with q-151
= (q-151+q)/(q)(q-151)
= (2q-151)/(q^2- 151q)

christoph always has good questions.
a truck of thanxxxxxx :wink:
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 [#permalink] New post 20 Oct 2005, 20:18
A too

just consider p=q-151 and plug :)
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 [#permalink] New post 20 Oct 2005, 21:11
nero44 wrote:
hehe I did this one again and now get a different result... letting q be the sum of integers..... I let p be q-151...

but then I get A....:S


:lol: You just have to make sure you are clear which is the bigger one ...
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keep on seeking, and you will find;
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  [#permalink] 20 Oct 2005, 21:11
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