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# ps - sum + sum ?

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VP
Joined: 30 Sep 2004
Posts: 1489
Location: Germany
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ps - sum + sum ? [#permalink]  20 Oct 2005, 11:31
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Difficulty:

(N/A)

Question Stats:

100% (02:30) correct 0% (00:00) wrong based on 0 sessions
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If your mind can conceive it and your heart can believe it, have faith that you can achieve it.

Manager
Joined: 04 Oct 2005
Posts: 246
Followers: 1

Kudos [?]: 21 [0], given: 0

BbBbBBBBBbBBbBbBBb.....

let q be sum of integers from 75 to 150
so p must simply be q + 151

1/q + 1/(q+151) ... rearrange and you get

2q + 151 / q^2 + q151
Current Student
Joined: 28 Dec 2004
Posts: 3390
Location: New York City
Schools: Wharton'11 HBS'12
Followers: 13

Kudos [?]: 182 [0], given: 2

LCM is q^2-151q

then q-151 goes into LCM q-151 times, and q goes q+151

so you have (q-151+q+151)/(q^2-151q)=2q/(q^2-151q)
Manager
Joined: 04 Oct 2005
Posts: 246
Followers: 1

Kudos [?]: 21 [0], given: 0

hehe I did this one again and now get a different result... letting q be the sum of integers..... I let p be q-151...

but then I get A....:S
Senior Manager
Joined: 05 Aug 2005
Posts: 414
Followers: 1

Kudos [?]: 12 [0], given: 0

Good one....

Q= p+151 so p=q-151

now solve 1/q-151 + 1/q ..... you will get A
SVP
Joined: 05 Apr 2005
Posts: 1732
Followers: 5

Kudos [?]: 39 [0], given: 0

A.

p= sum (75+76+77+............+150)
q= sum (75+76+77+............150+151)
q= sum (75+76+77+............150) +151
q= p+151
p= q-151

given that: 1/p+1/q = ?
= (p+q)/(pq)
replace p with q-151
= (q-151+q)/(q)(q-151)
= (2q-151)/(q^2- 151q)

christoph always has good questions.
a truck of thanxxxxxx
VP
Joined: 13 Jun 2004
Posts: 1122
Location: London, UK
Schools: Tuck'08
Followers: 7

Kudos [?]: 31 [0], given: 0

A too

just consider p=q-151 and plug
SVP
Joined: 03 Jan 2005
Posts: 2250
Followers: 13

Kudos [?]: 221 [0], given: 0

nero44 wrote:
hehe I did this one again and now get a different result... letting q be the sum of integers..... I let p be q-151...

but then I get A....:S

You just have to make sure you are clear which is the bigger one ...
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keep on seeking, and you will find;
keep on knocking, and it will be opened to you.

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