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PS : TRAIN (m09q09) [#permalink]
 27 Oct 2008, 00:59
The train consists of 6 carriages, 20 meters long each. The gap between the carriages is 1 meter. If the train is moving at a constant speed of 60 kmh, how much time will it take the train to run through a 1 kilometer tunnel? (A) 1\frac{1}{8} minutes (B) 1\frac{1}{2} minutes (C) 1\frac{3}{4} minutes (D) 2 minutes (E) 2\frac{1}{4} minutes Source: GMAT Club Tests - hardest GMAT questions
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1 1/8.
Total length of train = 20*6 + 5 (for gaps) = 125 meters.
Total distance required to cross tunnel = 1 km + 125m = 1.125 km.
Time required = (1.125/60)*60 minutes = 1.125 minutes = 1 1/8 minutes.
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scthakur wrote: 1 1/8.
Total length of train = 20*6 + 5 (for gaps) = 125 meters.
Total distance required to cross tunnel = 1 km + 125m = 1.125 km.
Time required = (1.125/60)*60 minutes = 1.125 minutes = 1 1/8 minutes. i made silly mistake 
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amitdgr wrote: scthakur wrote: 1 1/8.
Total length of train = 20*6 + 5 (for gaps) = 125 meters.
Total distance required to cross tunnel = 1 km + 125m = 1.125 km.
Time required = (1.125/60)*60 minutes = 1.125 minutes = 1 1/8 minutes. i made silly mistake I am into the same boat. I make silly mistakes all in a hurry.
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A - 1 1/8
1125/(60 * 1000) * 60 = 9/8 = 1 1/8
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Re: PS : TRAIN (m09q09) [#permalink]
06 Apr 2010, 05:02
amitdgr wrote: The train consists of 6 carriages, 20 meters long each. The gap between the carriages is 1 meter. If the train is moving at a constant speed of 60 kmh, how much time will it take the train to run through a 1 kilometer tunnel? (A) 1\frac{1}{8} minutes (B) 1\frac{1}{2} minutes (C) 1\frac{3}{4} minutes (D) 2 minutes (E) 2\frac{1}{4} minutes Source: GMAT Club Tests - hardest GMAT questions Train length = 6*20 + 1*5 = 125 m Total distance travelled = 1000 + 125 = 1125 m = 1.125 km = 1\frac{1}{8} km time taken for 1 km = 1 min hence A.
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Re: PS : TRAIN (m09q09) [#permalink]
06 Apr 2010, 08:52
Train Length = 6*20 + 5*1 = 125m
Total Distance = Tunnel+Train = 1000m+125m = 1125 m = 1 1/8 Km
Speed = 60KmpH = 1 Km/min
So, it will take 1 1/8 min to travel the total distance.
Hence A.
Prabir
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Re: PS : TRAIN (m09q09) [#permalink]
08 Apr 2011, 06:48
Answer is A. Posted from my mobile device 
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Re: PS : TRAIN (m09q09) [#permalink]
08 Apr 2011, 06:55
I will go with A 1 1/8
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Re: PS : TRAIN (m09q09) [#permalink]
08 Apr 2011, 07:03
amitdgr wrote: The train consists of 6 carriages, 20 meters long each. The gap between the carriages is 1 meter. If the train is moving at a constant speed of 60 kmh, how much time will it take the train to run through a 1 kilometer tunnel? (A) 1\frac{1}{8} minutes (B) 1\frac{1}{2} minutes (C) 1\frac{3}{4} minutes (D) 2 minutes (E) 2\frac{1}{4} minutes Source: GMAT Club Tests - hardest GMAT questions Length of the train = 6*20+5*1=125 meters Speed of the train = 60000/60 meters/min = 1000 meters/min Length of the tunnel = 1000 meters Total Distance = 1000+125=1125 meters Distance = Time*Speed 1125 = Time * 1000 Time = \frac{1125}{1000} = 1.125 = 1+ \frac{125}{1000} = 1+ \frac{1}{8}= 1\frac{1}{8}Ans: "A"
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Re: PS : TRAIN (m09q09) [#permalink]
08 Apr 2011, 07:08
Total Length of train = 6 * 20 + 5 * 1 = 125 m ||||||--||||||--||||||--||||||--||||||--|||||| So time required = (1000 + 125)/{(60) * (1000)} hrs = 1125/1000 * 60/60 min = 1.125 min = 1 1/8 min Answer - A
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Re: PS : TRAIN (m09q09) [#permalink]
08 Apr 2011, 11:22
Ans: A Took more than 2 mins
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Re: PS : TRAIN (m09q09) [#permalink]
12 Apr 2012, 07:05
amitdgr wrote: The train consists of 6 carriages, 20 meters long each. The gap between the carriages is 1 meter. If the train is moving at a constant speed of 60 kmh, how much time will it take the train to run through a 1 kilometer tunnel? (A) 1\frac{1}{8} minutes (B) 1\frac{1}{2} minutes (C) 1\frac{3}{4} minutes (D) 2 minutes (E) 2\frac{1}{4} minutes Source: GMAT Club Tests - hardest GMAT questions simple, but calculation is required... A is the answer clue to calculate it for 60km in 1 hr....and 125m long train to cross over 1km tunner will take another A mins... so calculate it for 1m - how much time from 60kmp and then apply for 125m length of train...n add 1+ the new value which gives A
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Re: PS : TRAIN (m09q09) [#permalink]
12 Apr 2012, 07:38
a)
for me the best approach is convert speed from km\h to m\min
and take the total length = Tunnel length + length of bogeys + gap in bogeys
just divide to get time in min
Glancing over the answers first to know that time required is in min can help
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Re: PS : TRAIN (m09q09) [#permalink]
12 Apr 2012, 08:20
A quick calculation yields that the distance = 1.125 km
Speed = 60kmph
From options : distance in 1[1][/2] = 1.5 km
Hence answer = A which is < 1[1][/2]
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Re: PS : TRAIN (m09q09) [#permalink]
12 Apr 2012, 10:51
Length of train = 20+1+20+1+20+1+20+1+20+1+20 = 125 meters
Speed of train = 1 km/minutes
Tunnel Length = 1 km so train has to travel 1 km + its own length = 1.125 km
1.125 minutes require to cross the tunnel i.e. 1(1/8)
so answer is A.
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Re: PS : TRAIN (m09q09) [#permalink]
05 Sep 2012, 06:00
A for me too Length is 125m Total distance travelled is length of tunnel + length of train = 1.125k To travel 60 km, train takes 60min To travel 1.125m, train takes 1.125 min. Hence A Posted from my mobile device
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Re: PS : TRAIN (m09q09) [#permalink]
06 Sep 2012, 09:47
I said, yeah it's 'A' then my mind said no way, you didn't do enough math...
Turns out I did.
Good question.
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Re: PS : TRAIN (m09q09) [#permalink]
15 Apr 2013, 05:24
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Re: PS : TRAIN (m09q09) [#permalink]
15 Apr 2013, 05:28
The train consists of 6 carriages, 20 meters long each. The gap between the carriages is 1 meter. If the train is moving at a constant speed of 60 kmh, how much time will it take the train to run through a 1 kilometer tunnel?
Net length of the train = 125m
Length of train = 1000m
Net distance = train length + train's own leangth = 1125 m
The train travels 60 km in 1 hr
=> to cover 1125 m it takes 1.125 min = 1 1/8 Hence A
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Re: PS : TRAIN (m09q09)
[#permalink]
15 Apr 2013, 05:28
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