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PS : TRAIN (m09q09)

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PS : TRAIN (m09q09) [#permalink] New post 26 Oct 2008, 23:59
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The train consists of 6 carriages, 20 meters long each. The gap between the carriages is 1 meter. If the train is moving at a constant speed of 60 kmh, how much time will it take the train to run through a 1 kilometer tunnel?

(A) 1\frac{1}{8} minutes
(B) 1\frac{1}{2} minutes
(C) 1\frac{3}{4} minutes
(D) 2 minutes
(E) 2\frac{1}{4} minutes

[Reveal] Spoiler: OA
A

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Re: PS : TRAIN [#permalink] New post 27 Oct 2008, 00:05
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1 1/8.

Total length of train = 20*6 + 5 (for gaps) = 125 meters.

Total distance required to cross tunnel = 1 km + 125m = 1.125 km.

Time required = (1.125/60)*60 minutes = 1.125 minutes = 1 1/8 minutes.
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Re: PS : TRAIN [#permalink] New post 27 Oct 2008, 00:13
scthakur wrote:
1 1/8.

Total length of train = 20*6 + 5 (for gaps) = 125 meters.

Total distance required to cross tunnel = 1 km + 125m = 1.125 km.

Time required = (1.125/60)*60 minutes = 1.125 minutes = 1 1/8 minutes.


i made silly mistake :(
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Re: PS : TRAIN [#permalink] New post 27 Oct 2008, 00:18
amitdgr wrote:
scthakur wrote:
1 1/8.

Total length of train = 20*6 + 5 (for gaps) = 125 meters.

Total distance required to cross tunnel = 1 km + 125m = 1.125 km.

Time required = (1.125/60)*60 minutes = 1.125 minutes = 1 1/8 minutes.


i made silly mistake :(


I am into the same boat. I make silly mistakes all in a hurry.
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Re: PS : TRAIN [#permalink] New post 27 Oct 2008, 02:43
A - 1 1/8

1125/(60 * 1000) * 60 = 9/8 = 1 1/8
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Re: PS : TRAIN (m09q09) [#permalink] New post 06 Apr 2010, 04:02
amitdgr wrote:
The train consists of 6 carriages, 20 meters long each. The gap between the carriages is 1 meter. If the train is moving at a constant speed of 60 kmh, how much time will it take the train to run through a 1 kilometer tunnel?

(A) 1\frac{1}{8} minutes
(B) 1\frac{1}{2} minutes
(C) 1\frac{3}{4} minutes
(D) 2 minutes
(E) 2\frac{1}{4} minutes

[Reveal] Spoiler: OA
A

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Train length = 6*20 + 1*5 = 125 m
Total distance travelled = 1000 + 125 = 1125 m = 1.125 km = 1\frac{1}{8} km
time taken for 1 km = 1 min
hence A.
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Re: PS : TRAIN (m09q09) [#permalink] New post 06 Apr 2010, 07:52
Train Length = 6*20 + 5*1 = 125m
Total Distance = Tunnel+Train = 1000m+125m = 1125 m = 1 1/8 Km
Speed = 60KmpH = 1 Km/min
So, it will take 1 1/8 min to travel the total distance.

Hence A.

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Re: PS : TRAIN (m09q09) [#permalink] New post 08 Apr 2011, 06:03
amitdgr wrote:
The train consists of 6 carriages, 20 meters long each. The gap between the carriages is 1 meter. If the train is moving at a constant speed of 60 kmh, how much time will it take the train to run through a 1 kilometer tunnel?

(A) 1\frac{1}{8} minutes
(B) 1\frac{1}{2} minutes
(C) 1\frac{3}{4} minutes
(D) 2 minutes
(E) 2\frac{1}{4} minutes

[Reveal] Spoiler: OA
A

Source: GMAT Club Tests - hardest GMAT questions


Length of the train = 6*20+5*1=125 meters
Speed of the train = 60000/60 meters/min = 1000 meters/min
Length of the tunnel = 1000 meters
Total Distance = 1000+125=1125 meters

Distance = Time*Speed
1125 = Time * 1000
Time = \frac{1125}{1000} = 1.125 = 1+ \frac{125}{1000} = 1+ \frac{1}{8}= 1\frac{1}{8}

Ans: "A"
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Re: PS : TRAIN (m09q09) [#permalink] New post 08 Apr 2011, 06:08
Total Length of train = 6 * 20 + 5 * 1

= 125 m

||||||--||||||--||||||--||||||--||||||--||||||

So time required = (1000 + 125)/{(60) * (1000)} hrs

= 1125/1000 * 60/60 min

= 1.125 min

= 1 1/8 min

Answer - A
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Re: PS : TRAIN (m09q09) [#permalink] New post 12 Apr 2012, 06:05
amitdgr wrote:
The train consists of 6 carriages, 20 meters long each. The gap between the carriages is 1 meter. If the train is moving at a constant speed of 60 kmh, how much time will it take the train to run through a 1 kilometer tunnel?

(A) 1\frac{1}{8} minutes
(B) 1\frac{1}{2} minutes
(C) 1\frac{3}{4} minutes
(D) 2 minutes
(E) 2\frac{1}{4} minutes

[Reveal] Spoiler: OA
A

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simple, but calculation is required... A is the answer

clue to calculate it for 60km in 1 hr....and 125m long train to cross over 1km tunner will take another A mins... so calculate it for 1m - how much time from 60kmp and then apply for 125m length of train...n add 1+ the new value which gives A
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Re: PS : TRAIN (m09q09) [#permalink] New post 12 Apr 2012, 06:38
a)

for me the best approach is convert speed from km\h to m\min
and take the total length = Tunnel length + length of bogeys + gap in bogeys

just divide to get time in min

Glancing over the answers first to know that time required is in min can help
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Re: PS : TRAIN (m09q09) [#permalink] New post 12 Apr 2012, 07:20
A quick calculation yields that the distance = 1.125 km

Speed = 60kmph

From options : distance in 1[1][/2] = 1.5 km

Hence answer = A which is < 1[1][/2]
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Re: PS : TRAIN (m09q09) [#permalink] New post 12 Apr 2012, 09:51
Length of train = 20+1+20+1+20+1+20+1+20+1+20 = 125 meters
Speed of train = 1 km/minutes
Tunnel Length = 1 km so train has to travel 1 km + its own length = 1.125 km

1.125 minutes require to cross the tunnel i.e. 1(1/8)

so answer is A.
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Re: PS : TRAIN (m09q09) [#permalink] New post 05 Sep 2012, 05:00
A for me too
Length is 125m
Total distance travelled is length of tunnel + length of train = 1.125k
To travel 60 km, train takes 60min
To travel 1.125m, train takes 1.125 min. Hence A

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Re: PS : TRAIN (m09q09) [#permalink] New post 06 Sep 2012, 08:47
I said, yeah it's 'A' then my mind said no way, you didn't do enough math...

Turns out I did.

Good question.
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Re: PS : TRAIN (m09q09) [#permalink] New post 15 Apr 2013, 04:24
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The train consists of 6 carriages, 20 meters long each. The gap between the carriages is 1 meter. If the train is moving at a constant speed of 60 kmh, how much time will it take the train to run through a 1 kilometer tunnel?

(A) 1\frac{1}{8} minutes
(B) 1\frac{1}{2} minutes
(C) 1\frac{3}{4} minutes
(D) 2 minutes
(E) 2\frac{1}{4} minutes

The length of the train is 6*20 plus five 1 meter gaps, so it's 6*20+5=125 meters;
The length that should be covered by train is 1+0.125=1.125 kilometers;

Time=\frac{Distance}{Rate}=\frac{1.125}{60} hours or \frac{1.125}{60}*60=1.125=1\frac{1}{8} minutes.

Answer: A.
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Re: PS : TRAIN (m09q09) [#permalink] New post 15 Apr 2013, 04:28
The train consists of 6 carriages, 20 meters long each. The gap between the carriages is 1 meter. If the train is moving at a constant speed of 60 kmh, how much time will it take the train to run through a 1 kilometer tunnel?

Net length of the train = 125m
Length of train = 1000m

Net distance = train length + train's own leangth = 1125 m

The train travels 60 km in 1 hr
=> to cover 1125 m it takes 1.125 min = 1 1/8 Hence A
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Re: PS : TRAIN (m09q09) [#permalink] New post 15 Apr 2013, 06:02
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amitdgr wrote:
The train consists of 6 carriages, 20 meters long each. The gap between the carriages is 1 meter. If the train is moving at a constant speed of 60 kmh, how much time will it take the train to run through a 1 kilometer tunnel?

(A) 1\frac{1}{8} minutes
(B) 1\frac{1}{2} minutes
(C) 1\frac{3}{4} minutes
(D) 2 minutes
(E) 2\frac{1}{4} minutes

[Reveal] Spoiler: OA
A

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a) It helps to keep a few pointers in mind always, and one such pointer is that 60KM/hr = 1 KM/min :)

b) For an object of "zero" length itself (like a point object), it would take 1 Minute to cross the tunnel

c) The train has a length of 6*20 + 5*1 = 125 m, or 0.125 KM; Using pointer in "(a)" above, it would take 0.125 or 1/8 minutes

Hence, total time to cross the tunnel is 1+ 1/8 minutes. Hence Option A.
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Re: PS : TRAIN (m09q09) [#permalink] New post 15 Apr 2013, 06:06
Total distance to cover = length of train + length of tunnel = (20*6 + 5)/1000 + 1 Km = 1.125 km
1 km is traveled in 60 min
--> 1.125 km is traveled in 1.125 min = 1 + 1/8 min

Answer is A.
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Re: PS : TRAIN (m09q09) [#permalink] New post 15 Apr 2013, 09:03
I will go with A

We need to consider whole length of the train. the moment it enters the cave till last carriage leave the cave that will add another 0.125. Rest iOS just applying the formula.
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Re: PS : TRAIN (m09q09)   [#permalink] 15 Apr 2013, 09:03
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