. If x and y are two-digit integers such that x > 40 and y<70, which of the following is closest to the maximum possible value of xy ?
My answer: Since X>40, then x can be any real number higher than 40, so why cannot 28000 be the answer. Please provide explanation and i will give the OA.
x is a 2 digit number so it cannot be > 99, which is close to 100.
y is also a 2 digit number but smaller than 70. so it can be 69, which is close to 70.
xy = 100x70 = 7,000.00