elmagnifico wrote:

. If x and y are two-digit integers such that x > 40 and y<70, which of the following is closest to the maximum possible value of xy ?

(A) 700

(B) 2,800

(C) 4,000

(D) 7,000

(E) 28,000

My answer: Since X>40, then x can be any real number higher than 40, so why cannot 28000 be the answer. Please provide explanation and i will give the OA.

good luck

x is a 2 digit number so it cannot be > 99, which is close to 100.

y is also a 2 digit number but smaller than 70. so it can be 69, which is close to 70.

xy = 100x70 = 7,000.00

_________________

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GT