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# PS two-digit integers

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Manager
Joined: 12 Feb 2008
Posts: 180
Followers: 1

Kudos [?]: 33 [0], given: 0

PS two-digit integers [#permalink]  30 Jan 2009, 12:35
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Question Stats:

0% (00:00) correct 100% (01:21) wrong based on 1 sessions
. If x and y are two-digit integers such that x > 40 and y<70, which of the following is closest to the maximum possible value of xy ?
(A) 700
(B) 2,800
(C) 4,000
(D) 7,000
(E) 28,000

My answer: Since X>40, then x can be any real number higher than 40, so why cannot 28000 be the answer.
Please provide explanation and i will give the OA.
good luck
SVP
Joined: 29 Aug 2007
Posts: 2493
Followers: 59

Kudos [?]: 577 [0], given: 19

Re: PS two-digit integers [#permalink]  30 Jan 2009, 13:16
elmagnifico wrote:
. If x and y are two-digit integers such that x > 40 and y<70, which of the following is closest to the maximum possible value of xy ?
(A) 700
(B) 2,800
(C) 4,000
(D) 7,000
(E) 28,000

My answer: Since X>40, then x can be any real number higher than 40, so why cannot 28000 be the answer. Please provide explanation and i will give the OA.
good luck

x is a 2 digit number so it cannot be > 99, which is close to 100.
y is also a 2 digit number but smaller than 70. so it can be 69, which is close to 70.
xy = 100x70 = 7,000.00
_________________
Re: PS two-digit integers   [#permalink] 30 Jan 2009, 13:16
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