PS tyre... PLEASE EXPLAIN : PS Archive
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09 Dec 2004, 09:51
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tyre.doc [25 KiB]

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09 Dec 2004, 10:17
Let Dia, Speed of small ring be Dsp, x respectively
and Large ring be Dsl,Nl respectively
& Vs & Vs be velocity in inches per sec

it is given that Vd = Vs
that is Pi * Dsp *x = Pi * Dsl * Nl

we get Nl = Rev/sec = 28/35*x

Rev/min = 28/35 * x * 60 = 48x
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Praveen

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09 Dec 2004, 13:23
Distance travelled by tyre = (circumference of tyre) * (# of revolutions per unit time)

"x" is the # of revolutions/ sec of smaller tyre S.
Ds = 28*pi*x (per second)

Let "y" be the # of revolutions/ sec of larger tyre L.
Dl = 35*pi*y (per second)

Given Ds= Dl

y = 4x/5

Revolution per minute = y*60 = 48x
09 Dec 2004, 13:23
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