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PS - x in terms of y

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PS - x in terms of y [#permalink] New post 03 Oct 2006, 21:22
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Could someone please advise how to do this algebraically (i.e not picking numbers).

Please express x in terms of y for the following and x>-2:

(x^2-16)/(x^2+6x+8)

Thanks
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 [#permalink] New post 04 Oct 2006, 06:07
Sorry guys you are right ...please set the equation to equal y

(x^2-16)/(x^2+6x+8) = y
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 [#permalink] New post 04 Oct 2006, 07:37
Matrix02 wrote:
Sorry guys you are right ...please set the equation to equal y

(x^2-16)/(x^2+6x+8) = y


FOIL the numerator and denominator.

(x+4)(x-4) / (x+4)(x+2)= y

Cancel out (x+4)

(x-4) / (x+2) = y ---> x-4= yx+2y ---> x-yx=2y+4 ---> x(1-y)=2y+4

x=(2y+4)/(1-y)
  [#permalink] 04 Oct 2006, 07:37
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