Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Pumps A, B, and C operate at their respective constant rates [#permalink]
10 Nov 2009, 14:14

3

This post received KUDOS

6

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

35% (medium)

Question Stats:

72% (02:34) correct
28% (01:27) wrong based on 525 sessions

Pumps A, B, and C operate at their respective constant rates. Pumps A & B, operating simultaneously, can fill a certain tank in 6/5 hours; Pumps A & C, operating simultaneously, can fill the tank in 3/2 hours, and pumps B & C, operating simultaneously can fill the tank in 2 hours. How many hours does it take pumps A, B, & C, operating simultaneously, to fill the tank?

Re: Practice Test Question (Rates) [#permalink]
10 Nov 2009, 14:35

12

This post received KUDOS

Expert's post

3

This post was BOOKMARKED

chicagocubsrule wrote:

Pumps A, B, and C operate at their respective constant rates. Pumps A & B, operating simultaneously, can fill a certain tank in 6/5 hours; Pumps A & C, operating simultaneously, can fill the tank in 3/2 hours, and pumps B & C, operating simultaneously can fill the tank in 2 hours. How many hours does it take pumps A, B, & C, operating simultaneously, to fill the tank?

a) 1/3 b) 1/2 c) 1/4 d) 1 e) 5/6

A and B = 5/6 --> 1/A+1/B=5/6 A and C = 2/3 --> 1/A+1/C=2/3 B and C = 1/2 --> 1/B+1/C=1/2

Q 1/A+1/B+1/C=?

Add the equations: 1/A+1/B+1/A+1/C+1/B+1/C=5/6+2/3+1/2=2 --> 2*(1/A+1/B+1/A+1/C)=2 --> 1/A+1/B+1/A+1/C=1

Re: Practice Test Question (Rates) [#permalink]
11 Nov 2009, 04:52

17

This post received KUDOS

Expert's post

4

This post was BOOKMARKED

chicagocubsrule wrote:

can you explain a little bit about adding the equations? Thanks

Generally, if we are told that: A hours is needed for worker A (pump A etc.) to complete the job --> the rate of A=\frac{1}{A}; B hours is needed for worker B (pump B etc.) to complete the job --> the rate of B=\frac{1}{B}; C hours is needed for worker C (pump C etc.) to complete the job --> the rate of C=\frac{1}{C};

You can see that TIME to complete one job=Reciprocal of rate. eg 6 hours needed to complete one job (time) --> 1/6 of the job done in 1 hour (rate).

Time, rate and job in work problems are in the same relationship as time, speed (rate) and distance.

Time*Rate=Distance Time*Rate=Job

Also note that we can easily sum the rates: If we are told that A is completing one job in 2 hours and B in 3 hours, thus A's rate is 1/2 job/hour and B's rate is 1/3 job/hour. The rate of A and B working simultaneously would be 1/2+1/3=5/6 job/hours, which means that the will complete 5/6 job in hour working together.

Time needed for A and B working simultaneously to complete the job=\frac{A*B}{A+B} hours, which is reciprocal of the sum of their respective rates. (General formula for calculating the time needed for two workers working simultaneously to complete one job). Time needed for A and C working simultaneously to complete the job=\frac{A*C}{A+C} hours.

Time needed for B and C working simultaneously to complete the job=\frac{B*C}{B+C} hours.

General formula for calculating the time needed for THREE workers working simultaneously to complete one job is:\frac{A*B*C}{AB+AC+BC} hours. Which is reciprocal of the sum of their respective rates: \frac{1}{A}+\frac{1}{B}+\frac{1}{C}.

We have three equations and three unknowns: 1. \frac{1}{A}+\frac{1}{B}=\frac{5}{6}

2. \frac{1}{A}+\frac{1}{C}=\frac{2}{3}

3. \frac{1}{B}+\frac{1}{C}=\frac{1}{2}

Now the long way is just to calculate individually three unknowns A, B and C from three equations we have. But as we just need the reciprocal of the sum of relative rates of A, B and C, knowing the sum of \frac{1}{A}+\frac{1}{B}+\frac{1}{C}=\frac{AB+AC+BC}{ABC} would be fine, we just take the reciprocal of it and bingo, it would be just the value we wanted.

If we sum the three equations we'll get: 2*\frac{1}{A}+2*\frac{1}{B}+2*\frac{1}{C}=\frac{5}{6}+\frac{2}{3}+\frac{1}{2}=2

\frac{1}{A}+\frac{1}{B}+\frac{1}{C}=1, now we just need to take reciprocal of 1, which is 1.

So the time needed for A, B, and C working simultaneously to complete 1 job is 1 hour.

What am I doing wrong ?? to Bunuel... [#permalink]
06 Mar 2010, 07:42

Pumps A, B, and C operate at their respective constant rates. Pumps A & B, operating simultaneously, can fill a certain tank in 6/5 hours; Pumps A & C, operating simultaneously, can fill the tank in 3/2 hours, and pumps B & C, operating simultaneously can fill the tank in 2 hours. How many hours does it take pumps A, B, & C, operating simultaneously, to fill the tank?

a) 1/3 b) 1/2 c) 1/4 d) 1 e) 5/6

We knw that a+b are taking 6/5 hrs i.e. 1.2 hrs to fill a tank... similarly B+C take 1.5 hrs and A+C take 2 hrs....

Adding all 3 equations we get

A+b + B+c + A+C = 1.2+1.5+2

2A+2B+2C = 4.7hrs A+B+C = 2.35 hrs

can u please guide where am I going wrong??? _________________

Therefore, 2A's, 2B's and 2C's working together would fill 2 tanks in an hour. A single A, B, and C working together would fill 1 tank in 1 hour. _________________

Emily Sledge | Manhattan GMAT Instructor | St. Louis

Re: Practice Test Question (Rates) [#permalink]
20 Apr 2011, 23:01

Bunuel wrote:

chicagocubsrule wrote:

can you explain a little bit about adding the equations? Thanks

Generally, if we are told that: A hours is needed for worker A (pump A etc.) to complete the job --> the rate of A=\frac{1}{A}; B hours is needed for worker B (pump B etc.) to complete the job --> the rate of B=\frac{1}{B}; C hours is needed for worker C (pump C etc.) to complete the job --> the rate of C=\frac{1}{C};

You can see that TIME to complete one job=Reciprocal of rate. eg 6 hours needed to complete one job (time) --> 1/6 of the job done in 1 hour (rate).

Time, rate and job in work problems are in the same relationship as time, speed (rate) and distance.

Time*Rate=Distance Time*Rate=Job

Also note that we can easily sum the rates: If we are told that A is completing one job in 2 hours and B in 3 hours, thus A's rate is 1/2 job/hour and B's rate is 1/3 job/hour. The rate of A and B working simultaneously would be 1/2+1/3=5/6 job/hours, which means that the will complete 5/6 job in hour working together.

Time needed for A and B working simultaneously to complete the job=\frac{A*B}{A+B} hours, which is reciprocal of the sum of their respective rates. (General formula for calculating the time needed for two workers working simultaneously to complete one job). Time needed for A and C working simultaneously to complete the job=\frac{A*C}{A+C} hours.

Time needed for B and C working simultaneously to complete the job=\frac{B*C}{B+C} hours.

General formula for calculating the time needed for THREE workers working simultaneously to complete one job is:\frac{A*B*C}{AB+AC+BC} hours. Which is reciprocal of the sum of their respective rates: \frac{1}{A}+\frac{1}{B}+\frac{1}{C}.

We have three equations and three unknowns: 1. \frac{1}{A}+\frac{1}{B}=\frac{5}{6}

2. \frac{1}{A}+\frac{1}{C}=\frac{2}{3}

3. \frac{1}{B}+\frac{1}{C}=\frac{1}{2}

Now the long way is just to calculate individually three unknowns A, B and C from three equations we have. But as we just need the reciprocal of the sum of relative rates of A, B and C, knowing the sum of \frac{1}{A}+\frac{1}{B}+\frac{1}{C}=\frac{AB+AC+BC}{ABC} would be fine, we just take the reciprocal of it and bingo, it would be just the value we wanted.

If we sum the three equations we'll get: 2*\frac{1}{A}+2*\frac{1}{B}+2*\frac{1}{C}=\frac{5}{6}+\frac{2}{3}+\frac{1}{2}=2

\frac{1}{A}+\frac{1}{B}+\frac{1}{C}=1, now we just need to take reciprocal of 1, which is 1.

So the time needed for A, B, and C working simultaneously to complete 1 job is 1 hour.

Hope it helps.

Nice Explanation.

Thanks for clearing the concepts. _________________

Re: Practice Test Question (Rates) [#permalink]
21 Apr 2011, 02:00

Bunuel wrote:

chicagocubsrule wrote:

can you explain a little bit about adding the equations? Thanks

Generally, if we are told that: A hours is needed for worker A (pump A etc.) to complete the job --> the rate of A=\frac{1}{A}; B hours is needed for worker B (pump B etc.) to complete the job --> the rate of B=\frac{1}{B}; C hours is needed for worker C (pump C etc.) to complete the job --> the rate of C=\frac{1}{C};

You can see that TIME to complete one job=Reciprocal of rate. eg 6 hours needed to complete one job (time) --> 1/6 of the job done in 1 hour (rate).

Time, rate and job in work problems are in the same relationship as time, speed (rate) and distance.

Time*Rate=Distance Time*Rate=Job

Also note that we can easily sum the rates: If we are told that A is completing one job in 2 hours and B in 3 hours, thus A's rate is 1/2 job/hour and B's rate is 1/3 job/hour. The rate of A and B working simultaneously would be 1/2+1/3=5/6 job/hours, which means that the will complete 5/6 job in hour working together.

Time needed for A and B working simultaneously to complete the job=\frac{A*B}{A+B} hours, which is reciprocal of the sum of their respective rates. (General formula for calculating the time needed for two workers working simultaneously to complete one job). Time needed for A and C working simultaneously to complete the job=\frac{A*C}{A+C} hours.

Time needed for B and C working simultaneously to complete the job=\frac{B*C}{B+C} hours.

General formula for calculating the time needed for THREE workers working simultaneously to complete one job is:\frac{A*B*C}{AB+AC+BC} hours. Which is reciprocal of the sum of their respective rates: \frac{1}{A}+\frac{1}{B}+\frac{1}{C}.

We have three equations and three unknowns: 1. \frac{1}{A}+\frac{1}{B}=\frac{5}{6}

2. \frac{1}{A}+\frac{1}{C}=\frac{2}{3}

3. \frac{1}{B}+\frac{1}{C}=\frac{1}{2}

Now the long way is just to calculate individually three unknowns A, B and C from three equations we have. But as we just need the reciprocal of the sum of relative rates of A, B and C, knowing the sum of \frac{1}{A}+\frac{1}{B}+\frac{1}{C}=\frac{AB+AC+BC}{ABC} would be fine, we just take the reciprocal of it and bingo, it would be just the value we wanted.

If we sum the three equations we'll get: 2*\frac{1}{A}+2*\frac{1}{B}+2*\frac{1}{C}=\frac{5}{6}+\frac{2}{3}+\frac{1}{2}=2

\frac{1}{A}+\frac{1}{B}+\frac{1}{C}=1, now we just need to take reciprocal of 1, which is 1.

So the time needed for A, B, and C working simultaneously to complete 1 job is 1 hour.

Hope it helps.

Serioulsy.. Nice explanation.. It will clear the basics for solving Time and Rate questions.. _________________

Re: What am I doing wrong ?? to Bunuel... [#permalink]
06 Jan 2012, 05:21

Nice problem and nice solution. Sum all the given rates and divide by 2. Take the reciprocal of the result to get our required answer. Answer: 1 hour Thanks Bunuel for amazing explanations. _________________

I am the master of my fate. I am the captain of my soul. Please consider giving +1 Kudos if deserved!

DS - If negative answer only, still sufficient. No need to find exact solution. PS - Always look at the answers first CR - Read the question stem first, hunt for conclusion SC - Meaning first, Grammar second RC - Mentally connect paragraphs as you proceed. Short = 2min, Long = 3-4 min

Pumps A, B, and C operate at their respective constant rates. Pumps A & B, operating simultaneously, can fill a certain tank in 6/5 hours; Pumps A & C, operating simultaneously, can fill the tank in 3/2 hours, and pumps B & C, operating simultaneously can fill the tank in 2 hours. How many hours does it take pumps A, B, & C, operating simultaneously, to fill the tank?

Re: Pumps A, B, and C operate at their respective constant rates [#permalink]
03 Mar 2013, 23:04

chicagocubsrule wrote:

Pumps A, B, and C operate at their respective constant rates. Pumps A & B, operating simultaneously, can fill a certain tank in 6/5 hours; Pumps A & C, operating simultaneously, can fill the tank in 3/2 hours, and pumps B & C, operating simultaneously can fill the tank in 2 hours. How many hours does it take pumps A, B, & C, operating simultaneously, to fill the tank?

Re: Pumps A, B, and C operate at their respective constant rates [#permalink]
27 Oct 2013, 03:13

chicagocubsrule wrote:

Pumps A, B, and C operate at their respective constant rates. Pumps A & B, operating simultaneously, can fill a certain tank in 6/5 hours; Pumps A & C, operating simultaneously, can fill the tank in 3/2 hours, and pumps B & C, operating simultaneously can fill the tank in 2 hours. How many hours does it take pumps A, B, & C, operating simultaneously, to fill the tank?

A. 1/3 B. 1/2 C. 1/4 D. 1 E. 5/6

Rate of A + B = 5/6 Rate of A + C = 2/3 Rate of B + C = 1/2

therefore 2(A + B + C) = 5/6 + 2/3 + 1/2 2(A + B + C) = 12/6 rate of A + B + C = 1

""HELP""Pumps A, B, and C operate at their respective rate. [#permalink]
19 Apr 2014, 05:16

I can't understand the reasoning behind this problem. Can you guys provide me an explanation?

Thanks you

Pumps A, B, and C operate at their respective rate. Pump A and B, operating simultaneously, can fill a certain tank in 6/5 hours; pumps A and C, operating simultaneously, can fill a certain tank in 3/2 hours; and pumps B and C, operating simultaneously, can fill a certain tank in 2 hours. How many hours does it take pumps A, B, and C, operating simultaneously, to fill the tank?

Re: ""HELP""Pumps A, B, and C operate at their respective rate. [#permalink]
19 Apr 2014, 08:28

Expert's post

plaintiff5 wrote:

I can't understand the reasoning behind this problem. Can you guys provide me an explanation?

Thanks you

Pumps A, B, and C operate at their respective rate. Pump A and B, operating simultaneously, can fill a certain tank in 6/5 hours; pumps A and C, operating simultaneously, can fill a certain tank in 3/2 hours; and pumps B and C, operating simultaneously, can fill a certain tank in 2 hours. How many hours does it take pumps A, B, and C, operating simultaneously, to fill the tank?

Merging similar topics. Please refer to the discussion above.

I´ve done an interview at Accepted.com quite a while ago and if any of you are interested, here is the link . I´m through my preparation of my second...

It’s here. Internship season. The key is on searching and applying for the jobs that you feel confident working on, not doing something out of pressure. Rotman has...