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Q 19 Challenge 25

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Manager
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Q 19 Challenge 25 [#permalink] New post 24 Apr 2006, 06:10
Guys,

Can you please help me understand this Co-Geom question. I read the explanation but I still don't understand.

Equation |x/2| + |y/2| =5 encloses a certain region in the coordinate plane. What is the area of this region?

a) 20
b) 50
c) 100
d) 200
e) 400

Can someone please help! Thanks
Manager
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GMAT Tests User
 [#permalink] New post 24 Apr 2006, 06:54
The equation given here forms 4 different line
since it's mod for both parameters it will generate 4 different line

y=10- x
y =x -10
y=10+x
y=-10-x

and from the above 4 you can find the coordinates where they cut x axis and y axis u will get 4 distinct points (10,0 ) (0,10) ,(-10,0) (0,-10)

because area of one traingle is (1/2 )* (10 *10) =50 and there are 4 such similar traingle so multiply it by 4 so it will be 50 * 4 =200

so from the above u can see the area is 4 * (1/2) * (10 *10) =200.

I hope the above explanation was clear enough to understand.
Manager
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 [#permalink] New post 24 Apr 2006, 20:48
Hi ipc302,

Thanks a ton, that really helps. I think I really need to brush up my cood-geom.

Thanks once again
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 [#permalink] New post 24 Apr 2006, 22:12
Answer is D....
It is a square... with sides = sqrt(10^2+10^2)
Manager
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 [#permalink] New post 25 Apr 2006, 06:14
Loner wrote:
Hi ipc302,

Thanks a ton, that really helps. I think I really need to brush up my cood-geom.

Thanks once again


Loner,

You are always welcome . Stick to this website and you will learn a lot . Visit verbal and other sections too . Good luck .
  [#permalink] 25 Apr 2006, 06:14
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