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Q: A certain jar contained only pennies and nickles. After 3

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Intern
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Q: A certain jar contained only pennies and nickles. After 3 [#permalink] New post 20 Nov 2005, 11:58
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Q: A certain jar contained only pennies and nickles. After 3 pennies were removed. how many nickels remained in the jar?
1. The original ration of pennies to nickles in the jar was 7:4
2. After the 3 pennies were removed, the ratio of pennies to nickles in the jar was 3:2
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 [#permalink] New post 20 Nov 2005, 12:17
C. 9
P : number of pennies initially
N : number of nickels initially

(1) P/N = 7/4
from ratio we cannot find exact value. insufficient

(2) (P-3/N) = 3/2

or 2P - 3N = 6
insufficient. 2 variables 1 eqn

together: 2 variables, 2 eqns
N = 12
N-3 = 9
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Re: DS-Ratio [#permalink] New post 22 Nov 2005, 00:39
C it is. My working is same as Duttist.
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 [#permalink] New post 22 Nov 2005, 12:09
Yea another C. If you know the before and after, you can calculate it...
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 [#permalink] New post 22 Nov 2005, 21:24
Another C. same method as duttsit 8-)
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 [#permalink] New post 22 Nov 2005, 21:39
number of pennies and nickles = x

Using (1), all we have is:
original number of pennies = 7x/11
original number of nickles = 4x/11
new number of pennies = 7x/11 - 3

(1) is not sufficient.

Using (2), can't solve either as all we have is the new ratio.

Using both, we can solve for x as we have the new ratio in terms of x and we know it's equal to 3:2.

Ans: C
  [#permalink] 22 Nov 2005, 21:39
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Q: A certain jar contained only pennies and nickles. After 3

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