Summer3 wrote:

Q: Is x > y ?

(1) x(x-1) > xy

(2) (x-y)^3 > 0

Solution:

(1) x(x-1) > xy

(x-1) > xy / x

x-1 > y

x > y+1 so x > y (A is SUFF)

(2) (x-y)^3 > 0

now x-y can not be negative because cube-root of negative is -ve. So x is either more than y or equal to y. x>=y

If x = y then e.g. (3-3)^3 > 0 => 0 > 0 which is NOT TRUE so B is NOT SUFF.

My answer is A alone SUFF.

Please check.

Hey Summer, why don't u please post just the question and then compare responses with your answer later? That way people will respond. If you post answers, how will we have fun in solving??