(1) (x + y)(x â€“ y) = 5! + 1

(2) x + y = 121

I think it's

A.
(1) (x + y)(x â€“ y) = 5! + 1

(x + y)(x â€“ y) = 121

i.e. (x + y)(x â€“ y) = 121 * 1

or (x + y)(x â€“ y) = 11 * 11

Now sum & difference of two numbers can't be same.

So, x+y = 121, x-y = 1,

Solving we get y = 60, x = 61. SO y!/x ! is not integer.

Hence 1 is SUFF.

(2) x + y = 121

Clearly not SUFF.

So A. _________________

If A equals success, then the formula is: A = X + Y + Z, X is work. Y is play. Z is keep your mouth shut.

Albert Einstein