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Q. The average (arithmetic mean) of the 5 positive integers

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Q. The average (arithmetic mean) of the 5 positive integers [#permalink] New post 11 Nov 2007, 06:33
Q. The average (arithmetic mean) of the 5 positive integers k, m, r, s, and t is 16, and k < m < r < s < t. If t is 40, what is the greatest possible value of the median of the 5 integers?

A. 16 B. 18 C. 19 D. 20 E. 22


I really appreciate your solutions..
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Re: (P/S) The average of k, m, r, s, and t [#permalink] New post 11 Nov 2007, 06:55
pretttyune wrote:
Q. The average (arithmetic mean) of the 5 positive integers k, m, r, s, and t is 16, and k < m < r < s < t. If t is 40, what is the greatest possible value of the median of the 5 integers?

A. 16 B. 18 C. 19 D. 20 E. 22


I really appreciate your solutions..


Picking the answer choices
start form C upwards

(K+M+R+S+T)/5=16
K+M+R+S+T=80
K+M+R+S+40=80
1+2+18+19+40=80
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Re: (P/S) The average of k, m, r, s, and t [#permalink] New post 11 Nov 2007, 07:31
Ravshonbek wrote:
pretttyune wrote:
Q. The average (arithmetic mean) of the 5 positive integers k, m, r, s, and t is 16, and k < m < r < s < t. If t is 40, what is the greatest possible value of the median of the 5 integers?

A. 16 B. 18 C. 19 D. 20 E. 22


I really appreciate your solutions..


Picking the answer choices
start form C upwards

(K+M+R+S+T)/5=16
K+M+R+S+T=80
K+M+R+S+40=80
1+2+18+19+40=80


How do you know the answer is 18 though ? I guess I just dont see why it couldnt be any of the other values ...
VP
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Re: (P/S) The average of k, m, r, s, and t [#permalink] New post 11 Nov 2007, 07:33
pmenon wrote:
Ravshonbek wrote:
pretttyune wrote:
Q. The average (arithmetic mean) of the 5 positive integers k, m, r, s, and t is 16, and k < m < r < s < t. If t is 40, what is the greatest possible value of the median of the 5 integers?

A. 16 B. 18 C. 19 D. 20 E. 22


I really appreciate your solutions..


Picking the answer choices
start form C upwards

(K+M+R+S+T)/5=16
K+M+R+S+T=80
K+M+R+S+40=80
1+2+18+19+40=80


How do you know the answer is 18 though ? I guess I just dont see why it couldnt be any of the other values ...


in order for median to be biggest K and M should be as minimum as possible. and they cannot be equal as stated in the stem. so min value for for them is 1 and 2.
then.
start picking nums from answer choices. best is from C. to find out where to go up or down as answer choices are given in ascending order. u will realize that u have to go up and end up with B
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Re: (P/S) The average of k, m, r, s, and t [#permalink] New post 11 Nov 2007, 07:41
Ravshonbek wrote:
in order for median to be biggest K and M should be as minimum as possible.


This is the key I was missing ! Thanks !

I always have trouble with these questions that ask for a min or a max .... is it a proper rule that when asked for the min or max, to set the other values to the opposite of what is being asked ?

I.E. If i want to maximize a value, set the others to the smallest possible ?
VP
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Re: (P/S) The average of k, m, r, s, and t [#permalink] New post 11 Nov 2007, 07:43
pmenon wrote:
Ravshonbek wrote:
in order for median to be biggest K and M should be as minimum as possible.


This is the key I was missing ! Thanks !

I always have trouble with these questions that ask for a min or a max .... is it a proper rule that when asked for the min or max, to set the other values to the opposite of what is being asked ?

I.E. If i want to maximize a value, set the others to the smallest possible ?


depends on questions. if there is no other quicker method picking numbers and starting form C then setting min and max would help a lot
Re: (P/S) The average of k, m, r, s, and t   [#permalink] 11 Nov 2007, 07:43
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Q. The average (arithmetic mean) of the 5 positive integers

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