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Q. When integer x is divided by 3, the remainder is 1; when

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Q. When integer x is divided by 3, the remainder is 1; when [#permalink] New post 12 Nov 2007, 03:42
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Q. When integer x is divided by 3, the remainder is 1; when x is divided by 5, the remainder is 1. If x+y is divisible by both 3 and 5, which of the following is the least value of positive integer y?

The answer is given as 14 but I can't find the solution for it.... Anybody please help me..
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 [#permalink] New post 12 Nov 2007, 04:04
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When integer x is divided by 3, the remainder is 1; when x is divided by 5, the remainder is 1

So x = 15 a +1

What must be added to it to make it divisible by 15

Ans is 14
  [#permalink] 12 Nov 2007, 04:04
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Q. When integer x is divided by 3, the remainder is 1; when

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