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# Y >= 0, What is the value of x? 1) |x-3|>=y 2) |x-3| <=-y

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Intern
Joined: 14 Mar 2010
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Y >= 0, What is the value of x? 1) |x-3|>=y 2) |x-3| <=-y [#permalink]

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14 Mar 2010, 01:03
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Question Stats:

38% (02:05) correct 63% (01:51) wrong based on 20 sessions

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Q) Y >= 0,
What is the value of x?

1) |x-3| >= y

2) |x-3| <= -y

OA:
[Reveal] Spoiler:
B

Q2) Is x+y<1?

(1) x < 8/9
(2) y < 1/8

OA:
[Reveal] Spoiler:
E
Senior Manager
Joined: 30 Aug 2009
Posts: 286
Location: India
Concentration: General Management
Followers: 3

Kudos [?]: 137 [0], given: 5

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14 Mar 2010, 01:44
shrutigoel wrote:
Q) Y >= 0,
What is the value of x?

1) |x-3| >= y

2) |x-3| <= -y

1. |x-3| >=Y

let Y = 0 then we have |X-3|>=0 . X can be 0,1,2,3. hence Insuff

2. |x-3| will always be +ve and we know Y >=0 so |x-3| <= -y will be true only for Y = 0.
we get |x-3| = 0. hence suff

B
Senior Manager
Joined: 30 Aug 2009
Posts: 286
Location: India
Concentration: General Management
Followers: 3

Kudos [?]: 137 [0], given: 5

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14 Mar 2010, 01:50
shrutigoel wrote:
Q2) Is x+y<1?

(1) x < 8/9
(2) y < 1/8

1. x< 8/9. Insuff as we dont know the value of y
2. y<1/8 .Insuff as we dont know the value of x

taking together we have x<8/9 and y< 1/8.
lets assume x = 63/72 < 64/72 or 8/9 and y = 8/72 < 9/72 or 1/8 so we have
x+y = 63/72 + 8/72 = 71/72 <1 hence suff

now lets assume x = 6399/7200 < 6400/7200 or 8/9 and y= 899/7200 < 900/7200 or 1/8 so we have
x+y = 6399/7200 + 899/7200 = 7298/7200 > 1. hence Insuff

So E
Re: inequality   [#permalink] 14 Mar 2010, 01:50
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# Y >= 0, What is the value of x? 1) |x-3|>=y 2) |x-3| <=-y

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